Answer: (3) In
Explanation: As the given compound is , it can be said that X has a valency of 3.
1)Barium (Ba): Atomic no: 56: : In order to complete its octet, it needs to donate 2 electrons, and thus the valency is 2.
2) Cadmium (Cd) : Atomic no: 48: : In order to complete its octet, it needs to donate 2 electrons, and thus the valency is 2.
3) Indium (In): Atomic no: 49: : In order to complete its octet, it needs to donate 3 electrons, and thus the valency is 3.
4) Sodium (Na): Atomic no: 11: : In order to complete its octet, it needs to donate 1 electron, and thus the valency is 1.
So the given element could only belong to the group containing Indium (In) as all the elements in the same group exhibit similar valency.
Horizontal if I am correct
Answer:
approximately 4.8 grams of oxygen gas is formed.
Explanation:
To determine the amount of oxygen (O2) formed when 12.26 grams of potassium chlorate (KClO3) is heated, we need to consider the chemical reaction that occurs during this process. When KClO3 is heated, it decomposes into potassium chloride (KCl) and oxygen gas (O2).
The balanced chemical equation for this reaction is:
2 KClO3(s) → 2 KCl(s) + 3 O2(g)
From the equation, we can see that 2 moles of KClO3 produce 3 moles of O2.
Calculate the molar mass of KClO3:
K: 39.10 g/mol
Cl: 35.45 g/mol
O: 16.00 g/mol
Molar mass of KClO3 = (39.10 + 35.45 + 3 * 16.00) g/mol = 122.55 g/mol
Calculate the number of moles of KClO3 in 12.26 grams:
Moles of KClO3 = (12.26 g) / (122.55 g/mol) = 0.1 moles
Now, we can determine the number of moles of O2 produced using the mole ratio from the balanced equation:
Moles of O2 = (0.1 moles of KClO3) * (3 moles of O2 / 2 moles of KClO3) = 0.15 moles
Finally, convert moles of O2 to grams:
Mass of O2 = (0.15 moles) * (32.00 g/mol for O2) = 4.8 grams
So, when 12.26 grams of KClO3 is heated, approximately 4.8 grams of oxygen gas is formed.
Answer:
62_grams of FeO
Explanation:
Molar mass of Fe = 55.845_g/mol
Molar mass of O2 = 15.999_g/mol
From law of conservation of mass
2 moles of Fe combines with one mole of O2 to form 2 moles of FeO
Number of moles of Fe and O2 present = mass/(molar mass) = 56/55.845~1
and 24/16 = 1.1.5
Therefore
1 part of Fe will react with 0.5 part of one mole of O2
which is 54_g of Fe reacts with 8_g to form 54+8 = 62_grams of FeO
Answer: Yes, lead ion will react with potassium iodide.
Explanation: When lead ion reacts with KI, a bright yellow colored precipitate is formed.
The reaction of these two follows:
Hence, ion reacts with KI to yield
This test is the confirmatory test for lead ion which is present in Group I.
Answer:
The factor by which the average kinetic energy of the oxygen molecules in the cylinder decreases is '0.5'.
Explanation:
Average kinetic energy is defined as the average of the kinetic energies of all the particles present in a system. It is determined by the equation:
where,
K = Average kinetic energy
R = Gas constant
T = Temperature of the system
= Avogadro's number
Average kinetic energy of oxygen gas molecule at 300 K.
..[1]
Average kinetic energy of oxygen gas molecule at 150 K.
..[2]
[1] ÷ [2]
The factor by which the average kinetic energy of the oxygen molecules in the cylinder decreases is '0.5'.
False
The correct answer its True
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