Answer:
The total number of students who have applied for the admissions in the school last year = 20000
Step-by-step explanation:
The school you want to go to has an acceptance rate of 12%.
⇒ 12% of the students who apply to the school get in
Now, Total number of students that are being selected = 2400
We need to find the total number of students those who have applied for the admission
Let the number of students who have applied for the admission be x
Now, using the condition given in the problem, we have :
12% of x = 2400
⇒ 0.12 × x = 240
⇒ x = 20000
Thus, The total number of students who have applied for the admissions in the school last year = 20000
Answer:
I think 1/16th of a pound
Step-by-step explanation:
Answer: 1/12
Step-by-step explanation: 1/4 divided by 3 is 1/12 if you multiply 1/12 by 3 you get 3/12 which simplifies to 1/4
Answer:
400 ft^2
Step-by-step explanation:
It can be shown that a square area is the most efficient way in which to use fencing. If the area is not square, the area will inevitably be smaller.
Calculus is the tool most often used in higher math to solve optimization problems.
But the same goal can be achieved in this problem by working with constraints:
If x and y are the length and width respectively, then
2x + 2y = 80 ft, or x + y = 40, or x = 40 - y. This is one constraint.
The other constraint involves the area: A = x*y, or A = (40 - y)*y. To maximize this, we need to rewrite (40 - y)*y in standard form:
A = 40y - y^2, or, finally, A = -y^2 + 40 y. The coefficients of this quadratic are -1, 40 and 0; the axis of symmetry is thus
x = -b/ [2a], or, in this case, x = -40/[2*(-1)], or x = 20.
Thus, If x = 20, y = 20 also, proving that the shape of the enclosed yard is that of a square.
Then Mrs. L' 80 feet of fencing is sufficient to construct a 20 ft by 20 ft space, which comes out to a maximum area of 400 ft^2.
40 -
b. 446/11
c. 89/14
d. 56
any answer is correct, my is correct....
Answer:
Number of cards at week n = 10,000(0.85)^(n-1).
At week 6 Dylan has 4437 cards.
Step-by-step explanation:
At the start of week 1 he had 10,000 = 10,000(0.85)^0 cards.
So at the start of week 2 he had 10,000(0.85)^(2-1) cards.
Number of cards for week n = 10,000(0.85)^(n-1).
Number of he will have at the start of the 6th week
= 10,000(0.85)^(6-1)
= 4437 cards (answer).