50 grams of acetic acid C2H4O2 are dissolved in 200 g of water. Calculate the weight % and mole fraction of the acetic acid in the solution

Answers

Answer 1

Answer: $50g$ $of$ $C_2H_4O_2$ $in$ $200g$ $H_2O$

so:

$(50)/(200+50)+100\%= (50*100)/(250)\%=20\%$

$MW of acid = 2*C+4*H+2*O = 2*12+4*1+2*16=$

$=24+4+32=60g/mol$

so:

$(50g)/(60g/mol)\approx0.83moles$

it means that

in $50g$ of acid there is $\approx0.83$ moles of acid

$MW of H_2O = 2*H+O=2*1+16=2+16=18g/mol$

so:

$(200g)/(18g/mol)\approx11.11moles$

it means that:

in $200g$ of water there is $\approx11.11$ moles of water

therefore:

$(0.83mol)/(11.11mol+0.83mol)= (0.83mol)/(11.94mol)=0.069$

So your answers are:

$20\%$

and the mole fraction is:

$0.069$

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Answers

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hope that's right and hope i helped

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Answers

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Answers

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Answers

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Answers

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