MATHEMATICS MIDDLE SCHOOL

Sin A - 2 sin cube A
---------------------------
2 cos cube A - cos A

Answers

Answer 1
Answer: (sin\alpha-2sin^3\alpha)/(2cos^3\alpha-cos\alpha)=(sin\alpha(1-2sin^2\alpha))/(cos\alpha(2cos^2\alpha-1))=(sin\alpha(1-sin^2\alpha-sin^2\alpha))/(cos\alpha(cos^2\alpha+cos^2\alpha-1))\n\n=(sin\alpha(cos^2\alpha-sin^2\alpha))/(cos\alpha(cos^2\alpha-sin^2\alpha))=(sin\alpha)/(cos\alpha)=tan\alpha\n\n\nsin^2\alpha+cos^2\alpha=1\to cos^2\alpha=1-sin^2\alpha\nsin^2\alpha+cos^2\alpha=1\to sin^2\alpha=1-cos^2\alpha\to-sin^2\alpha=cos^2\alpha-1

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Wallpaper was applied to one rectangular wall of a large room. The dimensions of the wall is 42 feet on one side and the other side 25.5 feet. If the total cost of the wallpaper was $771.12, what was the cost, in dollars, of the wallpaper per square foot?PLZ HELP ASAP!!!!!!!

Answers

Answer: $0.72


Step-by-step explanation:

Given The dimensions of the rectangular wall of a large room.

Length of the rectangular wall= 42 feet

Width of the rectangular wall= 25.5 feet

Then the area of the rectangular wall =length*\ width

=42*25.5=1071\ square feet

The cost of the wallpaper = $771.12

The cost of the wallpaper per square foot=\frac{\text{total cost of wallpaper}}{\text{area of the wall}}

=(771.12)/(1071)\n\n=(77112)/(107100)=(72)/(100)=\$0.72

Hence, the cost of the wallpaper per square foot = $0.72
.72¢ per square foot. 
In order to find this answer, first you need to find out how many square feet the wall is. Multiply the dimensions ( 42 x2 5.5), and that would give you the answer. (1,071). Now that we have the total square footage, you can cross multiply to find out how much 1 square foot would cost.    1,071       1
                                                                                          –––––– x ––––
                                                                                           771.12.      ?
Cross multiply to get the answer .72

There is 1/4 ounce of yeast in every 2 1/4 teaspoons of yeast. A recipe for bread calls for 2 teaspoons of yeast. How many ounces of yeast are needed for this recipe?

Answers

Answer: 2/9 ounces of yeast are needed.

1) 3 - 7 x 5 + 2 x 4=2) 7 - 2 x 5 + 9 x 3=

3) 2 - 8x + 3x When x = 5

4) 4 - 2x + 5x when x= 4

5) z divided 2 - 4z + 3(z-3) when z =8

Answers

1) -24

2) 24

3) -23

4) 16

5) -8/15

Please give me brainliest answer. I need it to level up!

GEMDAS!

1:

3 - 7 x 5 + 2 x 4

3 - 35 + 2 x 4

3 - 35 + 8

3 - 27

-24


2:

7 - 2 x 5 + 9 x 3

7 - 10 + 9 x 3

7 - 10 + 27

7 + 17

24


3:

2 - 8x + 3x When x = 5

2 - 8(5) + 3(5)

2 - 40 + 15

2 - 25

-23


4:

4 - 2x + 5x when x= 4

4 - 2(4) + 5(4)

4 - 8 + 20

4 + 12

16


5:

z ÷ 2 - 4z + 3(z - 3) when z = 8

8 ÷ 2 - 4(8) + 3(8 - 3)

8 ÷ 2 - 32 + 24 - 9

4 - 32 + 24 - 9

4 - 8 - 9

-13


I might've did #5 incorrect.... Really really sorry...

2x +4- 3 (x + 5) = -2x + 4
x=-26
X=15
X=-5
x=-15

Answers

2x+4 -3x -15=-2x+4

-1x-11=-2x+4

-11=-1x +4

-15=-1x

15=c

A circle with a radius of 4 in, is dilated by a scale factor of 5. What will be the circumference of the circle after dilation?21 in
4 in
161 in
24 in

Answers

Ok so circumference=2*pi*radius. So We know that the radius is dilated by a scale factor of 5, so we can put 2*pi*20. For pi you can use So when we multiply 2*pi*20, you get 125.6637

Consider the relation. {(–3, 2), (–1, 3), (–1, 2), (0, 4), (1, 1)} Determine which best describes the given relation. The given relation is not a function because the input of –1 has two outputs of 2 and 3. The given relation is a function because the input of –1 has two outputs of 2 and 3. The given relation is a function because the output of 2 has two inputs of –1 and –3. The given relation is not a function because the output of 2 has two inputs of –1 and –3.

Answers

 The given relation is not a functionbecause the input of –1 has two outputs of 2 and 3
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