Round 8.54 to nearest tenth

Answers

Answer 1

Answer: If you look at the image below, you can find what the tenths place is.
Juts follow the rule: 5 or more raise the score, 4 or less stay and res(t)
Therefore 8.54 would raise to 8.5 Since the four is lower than five, it rounds down.
~Hope this helped :)

Answer 2

Answer: If the last number is less than 5, you will not round the number next to it, if the number is more than 5 or 5, you'll round
So the answer to this question is 8.5

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1How can you arrange the digits 5,3,0 to create the greatest decimal possible? You can only use each digit once and you do not have to use all of the digits.

Answers

Answer:

0.530 (the 0 is not required)

Step-by-step explanation:

this is because another combination would be .35 which is less than .53 so this what i think the answer is.

--hope this helped :))

The equation y = 17x shows that a boat travels at a speed of 17 km/h. Which ordered pair satisfies the equation y = 17x? A. (0, 0) B. (0, 17) C. (1, 18) D. (17, 1) PLEASE HELP ASAP!

Answers

A, (0,0) is the answer

Find k if (x-3) is a factor of $k^(2) x^(2) -kx-2$ .

Answers

$w(x)=k^2x^2-kx-2\n\n(x-3)\ is\ a\ factor\ w(x)\ then\ w(3)=0.\n\nSubstitute:\n\nk^2\cdot3^2-k\cdot3-2=0\n9k^2-3k-2=0\n9k^2-6k+3k-2=0\n3k(3k-2)+1(3k-2)=0\n(3k-2)(3k+1)=0\iff3k-2=0\ \vee\ 3k+1=0\n3k=2\ \vee\ 3k=-1\n\n\underline{\underline{k=(2)/(3)\ \vee\ k=-(1)/(3)}}$

k can be (-1/3) or (2/3).
since (x-3) is a factor. if you put x=3 in the equation, it must be equal to zero. So the equation becomes (9k2 - 3k -2 = 0). if you solve this you will get k=(-1/3) and k=(2/3). You can substitute this k in the original equation and check, (x-3) is a factor.

Students in Miss Moseley's fourth grade class are learning multiplication, and they demonstrate mastery by passing assessments. Travis has passed 11 tests, and his classmate, Jenifer, has passed 2 tests. Going forward, Travis plans to pass 2 tests per week. Meanwhile, Jenifer plans to pass 5 tests per week. Eventually Jenifer will catch up to Travis. When the number of tests each student has passed are equal, how many tests will each student have passed and how many weeks will it take?