MATHEMATICS MIDDLE SCHOOL

What is the surface area of the square pyramid? A.


340 cm2


B.


280 cm2


C.


220 cm2


D.


160 cm2
What is the surface area of the square pyramid? A. - 1

Answers

Answer 1
Answer: I was Thinking it out on my art pad
A=(1/2)
bh A=(1/2)*10*12
A=5*12=60 sq cm
 4*60=240 sq cm
 A=s*s A=10*10=100 sq cm
 240+100=340 sq cm
so A

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Martha is covering kitchen shelves with shelving paper. She has 6 shelves that are each 1 3 4 feet long. She buys 13 1 4 feet of shelving paper of the correct width. Which equation can be used to determine how much paper she will have left over?

Answers

The equation to determine the amount of left over kitchen shelving paper is; L = 53/4 - (21/2)x.

What is the definition of the mixed fractions?

  • A mixed fraction is just a type of fraction that has both a whole number and a fractional part.
  • An improper fraction may also be formed from a mixed fraction.

For the given question;

Martha purchased 6 kitchen shelves with shelving paper.

The length of 6 shelves is 1 3/4 feet = 7/4 feet.

Thus, the total length of the 6 shelving papers is 6× 7/4 = 21/2 feet

The corrected width of the shelving paper is 13 1/4 = 53/4 feet.

The equation to defined the left over papers 'L'.

Let number of shelves be 'x'.

L = 53/4 - (21/2)x.

Thus, the equation to determine the amount of left over kitchen shelving paper is; L = 53/4 - (21/2)x.

To know more about the mixed fractions, here

brainly.com/question/28306054

#SPJ2

The correct question is-

Martha is covering kitchen shelves with shelving paper. She has 6 shelves that are each 1 3/4 feet long. She buys 13 1/4 feet of shelving paper of the correct width. Which equation can be used to determine how much paper she will have left over?

The correct expression is 13 1/4 − 6(1 3/4) = S. You take the total amount you have and subtract how much you need, 6 shelves each 1 3/4 feet long.

Find the minimum, maximum, range, mean, and median for the data set. 12, 13, 13, 17, 18, 19, 27

A.
minimum: 12
maximum: 27
range: 15
mean: 17
median: 13

B.
minimum: 27
maximum: 12
range: 15
mean: 17
median: 17

C.
minimum: 12
maximum: 27
range: 15
mean: 17
median: 17

D.
minimum: 12
maximum: 27
range: 17
mean: 15
median: 17

Answers

Hi There! :)

Find the minimum, maximum, range, mean, and median for the data set.12, 13, 13, 17, 18, 19, 27

A.
minimum: 12 
maximum: 27 
range: 15 
mean: 17 
median: 13

B.
minimum: 27 
maximum: 12 
range: 15 
mean: 17 
median: 17

C.
minimum: 12 
maximum: 27 
range: 15 
mean: 17 
median: 17

D.
minimum: 12
maximum: 27 
range: 17 
mean: 15 
median: 17

minimum: 12 maximum: 27 range: 15 mean: 17 median: 17

Two box plots have the same median and equally long whiskers.If one box plot has a longer box than the other box plot, what does this tell you about the difference between the data sets?

Answers

The first line as you know is the lowest value
The second line (start of box) is the lower quartile
The Middle line is the median
The fourth line (End of box) is the upper quartile 
The last line is the highest value
A box plot with a longer box shows that interquartile range is likely to be larger suggesting more of a spread in data.

Answer:

A   hope this helps!

Step-by-step explanation:

  • The box range is 22 to 29

  • The dividing line of the box is at 24 is the median

  • For minivans

  • The range given as Minimum = 14 and Maximum = 26

  • The range of the whiskers is 14 to 26

  • The box range is 18 to 21

  • The dividing line of the box is at 19 is the median

  • Therefore, the range of the box plot for cars is the difference of the values at the ends of the whiskers, that is 33 - 21 = 8

  • The range for minivan = 26 - 12 = 14

  • Therefore, Josef's error is that, Josef confused the range and the interquartile range.

The longest side of an isosceles obtuse triangle measures 20 centimeters. The other two side lengths are congruent but unknown.What is the greatest possible whole-number value of the congruent side lengths?

A.9 cm
B.10 cm
C.14 cm
D.15 cm

Answers

Since 9+9=19<20 and 10+10=20=20, the triangles with sides 9, 9, 20 and 10, 10, 20 cannot exist.

Use the cosine theorem to check which option C or D is true:

1.

20^2=14^2+14^2-2\cdot 14\cdot 14\cos \theta,\n 400=196+196-392\cos \theta,\n 8=-392\cos \theta,\n \n \cos \theta=-(8)/(392) =-(1)/(49).

You have that cosine of the greatest angle (opposite to the greatest side) is negative, this means that angle is obtuse.

2.

20^2=15^2+15^2-2\cdot 15\cdot 15\cos \theta,\n 400=225+225-450\cos \theta,\n -50=-450\cos \theta,\n \n \cos \theta=(50)/(450) =(1)/(9).

Here you have that cosine of the greatest angle (opposite to the greatest side) is posiative, this means that angle is acute.

Answer: the greatest possible whole-number value of the congruent side lengths is 14 (choice C)

Answer:

c

Step-by-step explanation:

Draw a shape using a rectangle and a triangle

Answers

put the rectangle under the triangle to make a pentagon.

David wants to buy 3 avacados and some apples. The price of 1 avocado is $1.50. The prices of apples is $1.00 per pound. David can spend less than $15. Write an inequality that represents the avacado and the number of pounds of apples (a) David can buy.

Answers

Since David has to buy the avocadoes, we can multiply 3 by $1.50, which gives us $4.50 and will be a constant in the equation
Only the number of pounds of apples can vary (we will name the variable 'p')
Since he can spend LESS than 15, we have to use the sign <

If we combine it all together we get:
4.50+1.00p<15
4.5+p<15
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