Write an equation to represent the possible numbers of cats and dogs that could have been at the
shelter on Wednesday.
Pat said that there might have been 8 cats and 14 dogs at the shelter on Wednesday. Are Pat’s
numbers possible? Use your equation to justify your answer.
Later, Pat found a record showing that there were a total of 22 cats and dogs at the shelter on
Wednesday. How many cats were at the shelter on Wednesday?
The equation representing the costs to care for the animals is 2.35c + 5.5d = $89.50. Pat's proposal of 8 cats and 14 dogs does not match the costs. Upon using additional information of the total number of animals being 22, we can solve the system of equations to find that there were 16 cats and 6 dogs at the shelter on Wednesday.
Let's denote the number of cats as c and the number of dogs as d. We know from the cost of care per day per animal that 2.35c + 5.5d = $89.50. This is the equation representing the possible number of cats and dogs at the shelter in terms of costs. For Pat's numbers, we can substitute c=8 and d=14 into the equation and check if they are possible. That is, substitute and check if 2.35(8) + 5.5(14) equals to 89.5. In this case, it does not since the total here comes to more than $89.50. So, Pat's numbers were not possible.
Regarding the total number of animals, we know that c + d = 22. With this equation, we can solve the system of equations to find out the actual number of cats and dogs at the shelter on Wednesday. Solving these two equations, we will find that 16 cats and 6 dogs were present at the shelter on Wednesday.
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Answer:4.1
Step-by-step explanation:
Answer: 4.1
Step-by-step explanation:
Oy= (x + 7) (x - 2)
Oy= (x - 5)(x – 14).
Oy= (x + 5) (x + 14)
Need help ASAP PLS
Answer:
Y = (x - 7) (x + 2)
Step-by-step explanation:
I need some help
Hi Walker
d=a+b+c
Flip
a+b+c=d
Add -a to both sides
a+b+c-a=d-a
b+c=-a+d
Now add -c to both sides
b+c-c=-a+d-c
b= -a-c+d
I hope that's help:0