The area tjhat he can cover with these tiles is 77 ¹¹/₃₂ in²
To solve the above questions, we need to recall some of the formulas as follows:
Area of Square = (Length of Side)²
Perimeter of Square = 4 × (Length of Side)
Area of Rectangle = Length × Width
Perimeter of Rectangle = 2 × ( Length + Width )
Area of Rhombus = ½ × ( Diagonal₁ + Diagonal₂ )
Perimeter of Rhombus = 4 × ( Length of Side )
Area of Kite = ½ × ( Diagonal₁ + Diagonal₂ )
Perimeter of Kite = 2 × ( Length of Side₁ + Length of Side₂ )
Let us now tackle the problem !
Given:
Number of Tiles = N = 9 tiles
Length of Tiles = L = 3¹/₈ inches
WIdth of Tiles = W = 2³/₄ inches
Unknown:
Total Area = A = ?
Solution:
Area of One Tile.
Total Area.
Grade: College
Subject: Mathematics
Chapter: Two Dimensional Figures
Keywords: Perimeter, Area , Square , Rectangle , Side , Length , Width
-8*(-3)
-24
Answer:
24
Step-by-step explanation:
Multiply −8 by −3 =24
two negatives = a positive answer
a negative and a positive = a negative answer
two positive = positive answer
Answer:
n=1
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Answer:
30n²+54+24n
Step-by-step explanation:
5nX6n=30n²
5nX6n=30n²5nX6=30
5nX6n=30n²5nX6=304X6n=24n
5nX6n=30n²5nX6=304X6n=24n4X6=24
=30n²+30+24n+24
=30n²+54+24n
A.
2x + y = –3
B.
2x – y = –3
C.
–4x + y = –3
D.
2x + y = 13