In 9 minutes, an athlete can run 2 kilometers. Express the athlete's average speed in meters per second. Round to the nearest tenth.

Answers

Answer 1

Answer:
(2 km/ 9 minutes) x (1,000 m/km) x ( 1 minute/60sec) =

(2 x 1,000) / (9 x 60) m/sec = 3.7 m/s

Answer 2

Answer:

.27 is the final answer message for work

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The perimeter, P, of a rectangle is found using the formula P = 2l + 2w, where l is the length of the rectangle and w is the width of the rectangle.Solve the formula for w.

Answers

The required formula width of the rectangle in terms of w is $x = (p-2L)/(2)$ .

Given ,

The perimeter of a rectangle = p

Formula = P = 2l + 2w,

Where, l is the length of the rectangle and w is the width of the rectangle.

We have to find

The formula in terms of w width.

According to the question,

The formula of a rectangle is P (perimeter) = 2W (the two widths added together) + 2L (the two lengths added together).

Now ,

Let "x" is often used, and solve for x. You could keep W instead of X also.

P= 2x + 2L

isolate the 2x by subtracting2L from both sides.

P - 2L= 2x

Now isolate the x by dividing both sides by 2 and ,

$x = (p-2L)/(2)$

Where, x = w,

$w = (p-2L)/(2)$

Hence, The required formula width of the rectangle in terms of w is $x = (p-2L)/(2)$

For more information about Perimeter of rectangle click the link given below.

brainly.com/question/2589784

Answer:The formula to find the perimeter of a rectangle is: P = 2W + 2L. To solve for " W " in this formula, which steps should be followed?

Step-by-step explanation:

E. 65,124 rounded to the nearset thousand is f. 99,451 rounded to the nearest thousand is

g. 60,488 rounded to the nearest ten thousand is

h. 80,801 rounded to the nearest ten thousand is

i. 897,100 rounded to the nearest ten thousand is

j. 880,005 rounded to the nearest hundred thousand is

k. 545,999 rounded to the nearest hundred thousand is

l. 689,114 rounded to the nearest hundred thousand is

Answers

Answer:

e. 65,000

f. 99,000

g. 60,000

h. 80,000

i. 900,000

j. 900,000

k. 500,000

l. 700,000

Step-by-step explanation:

Since, when we round a number to the nearest thousand then we check the digit at hundred place,

If the hundred place digit is less than 5 then the number is rounded to previous thousand,

If the digit is 5 or more than 5 then the number is rounded to next thousand,

So, 65,124 ≈ 65,000

99,451 ≈ 99,000

The above procedure is follow in rounding both nearest ten thousand and hundred thousand,

But, in rounding nearest ten thousand and hundred thousand we check thousand place digit and ten thousand place digit respectively,

Hence, 60,488 ≈ 60,000

80,801 ≈ 80,000

897,100 ≈ 900,000

880,005 ≈ 900,000

545,999 ≈ 600,000

689,114 ≈ 700,000

e. 65,000
f. 99,000
g. 60,000
h. 80,000
I. 900,000
j. 900,000
k.500,000
l. 700,000

What does reciprocal mean?

Answers

you have to flip a fraction or number to get the reciprocal.

The reciprocal of a fraction is the fraction turned upside-down. For example the reciprocal of 2/3 is 3/2 , or as a mixed number: 1 1/2

Mumbi is approximately 845 kilometers away from Bangalore, and Mumbai is approximately 1160 km away from Delhi. The distances, measured in centimeters between cities on Allyson’s map are proportional to the real distances.Which of the following could be the the distances on Allyson’s map?

Choose 3 answers

Bangalore to Mumbai: 116.5 cm
Mumbai to Delhi: 174 cm

Bangalore to Mumbai: 42.25
Mumbai to Delhi: 58 cm

Bangalore to Mumbai: 23.4 cm
Mumbai to Delhi: 29 cm

Bangalore to Mumbai: 16.9 cm
Mumbai to Delhi: 23.2 cm

Bangalore to Mumbai: 25.35 cm
Mumbai to Delhi: 34.8cm

Answers

Mumbi is approximately 845 kilometers away from Bangalore, and Mumbai is approximately 1160 km away from Delhi, then the ratio between these distances is

$(845)/(1160)=(169)/(232).$

A. Bangalore to Mumbai: 116.5 cm;

Mumbai to Delhi: 174 cm

The ratio:

$(116.5)/(174)=(233)/(348)\neq (169)/(232)$

This option is false.

B. Bangalore to Mumbai: 42.25

Mumbai to Delhi: 58 cm

The ratio is

$(42.25)/(58)=(845)/(1160)=(169)/(232)$

This option is true.

C. Bangalore to Mumbai: 23.4 cm

Mumbai to Delhi: 29 cm

The ratio is

$(23.4)/(29)=(117)/(145)\neq (169)/(232)$

This option is false.

D. Bangalore to Mumbai: 16.9 cm

Mumbai to Delhi: 23.2 cm

The ratio is

$(16.9)/(23.2)=(169)/(232)$

This option is true.

E. Bangalore to Mumbai: 25.35 cm

Mumbai to Delhi: 34.8cm

The ratio is

$(25.35)/(34.8)=(507)/(696)=(169)/(232)$

This option is true.

Answer: correct options are B, D and E

Answer:

Step-by-step explanation:

Mumbi is approximately 845 kilometers away from Bangalore, and Mumbai is approximately 1160 km away from Delhi, then the ratio between these distances is

A. Bangalore to Mumbai: 116.5 cm;

Mumbai to Delhi: 174 cm

The ratio:

This option is false.

B. Bangalore to Mumbai: 42.25

Mumbai to Delhi: 58 cm

The ratio is

This option is true.

C. Bangalore to Mumbai: 23.4 cm

Mumbai to Delhi: 29 cm

The ratio is

This option is false.

D. Bangalore to Mumbai: 16.9 cm

Mumbai to Delhi: 23.2 cm

The ratio is

This option is true.

E. Bangalore to Mumbai: 25.35 cm

Mumbai to Delhi: 34.8cm

The ratio is

This option is true.

Answer: correct options are B, D and E

15-4t=3 how do i solve this in words

Answers

-4t = -15 + 3

Divide both sides by -4.

T= -15/4 -1

Point D is on segment SF. If SF is 72 cm and DF is 62, what is the measurement of segment SD ?

Answers

SD=SF-DF
SD=72-62=10cm

If D is on segment SF then |SD| + |DF| = |SF|.

We have:

|SF| = 72 cm
|DF| = 62 cm

substitute:

|SD| + 62 cm = 72 cm |-62 cm

|SD| = 10 cm

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