Given that a plumber charges $110 per hour. Where h represents the number of hours worked by plumber.
Then profit equatio for the plumber is given by P=110h
where P gives total earning of the plumber in h hours.
Now we need to find about what domain values are relevant on a graph that shows his earnings. Graph is not given but that is not the problem.
We know that number of hours can never be negative. It can be 0 or more.
Hence domain for the graph will be "all positive real numbers" which can also be written as:
h≥0.
Maximum hours is not given neither it is specified to use data for how many days so we will not put any upper bound for h.
Answer:
h ≥ 0
Step-by-step explanation:
The equation of his earnings is $110h. He can't work negative hours.
62,732+469=63,201
63,201+62,732=125,933
your answer is 125,933
y = one-half x + 6 and y = negative three-fourths x minus 4
A. (–8, 2)
B. (–8, –1)
C. (8, 10)
D. (8, –10)
Answer: 237.5%
Step-by-step explanation:
2 = 2
3/8 = 0.375
0.375 + 2 = 2.375
to make a percent multiply by 100
2.375 • 100 = 237.5%