The equation of line which passes through (3, 1) and perpendicular to y = -3x + 2 is;
⇒ x = 3y
Here,
Given that;
The point is (3, 1).
We have to find the equation which passes through (3, 1) and perpendicular to y = -3x + 2.
What is equation of line passes through a point?
Equation of line passes through a point (a, b) with slope m is;
⇒ (y - a) = m (x - b)
Now,
As it is perpendicular to y = -3x + 2 and the slope of this is m₁ = -3,
Hence, the slope of to find line is m₂ = -1 / -3 = 1/3
We have the general equation of a line;
( y - y₁ ) = m₂ (x - x₁)
Where, ( x₁ , y₁ ) = (3, 1) and m₂ = 1/3
So, after putting all values we get;
( y - 1 ) = 1/3 ( x - 3)
3 (y - 1) = (x - 3)
3y - 3 = x - 3
3y = x
x = 3y
Hence, The equation of line which passes through (3, 1) and perpendicular to y = -3x + 2 is;
⇒ x = 3y
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Answer:
QRU and VUR
Step-by-step explanation:
Alternative interior angles are angles that have the same degrees, but different locations. In this case, you can see QRU has the same degree of angle as VUR; They are only in different locations.
- Hope that helps! Please let me know if you need further explanation.
Answer:
QRU and VUR
Step-by-step explanation:
Hope this helps!
Solution:
Coordinates of Point E and F are (-2,4) and (5,10).
Suppose the Point M(x,y), divides the Line Segment Joining E (-2,4) and F (5,10) in the 7:3 ratio.
So, EM: MF= 7:3
Formula for internal Division
So,we get
x= 2.9
and , y= 8.2