A recipe requires 2.5 cups of peaches for 6 servings. What amount of peaches is required for 1 serving?
Answers
x cups per 1 serving
2.5 / 6 = x
The cups needed would be approximately 0.42 for one serving.
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Equivalent to log3(x+4)
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Jill says that 12.6666666 is less than 12.63 explain Her error
Answers
7 ft × 2 (widths)
12 ft × 2 (lengths)
5 ft (height of prism)
Formula of the surface area of a prism is:
2 × Area of base + Perimeter × Height of prism
Area of rectangle (length × width)
Perimeter of rectangle (2×length + 2×width)
2 × (12 × 7) +(2×12+2×7) × 5
168 + 190
358 ft²
LOL NOT GIVING YOU ANSWERS CHEATERS JUST JOINED TO TROLL
Answers
We have
425 corresponds to a z of
575 corresponds to
So we want the area of the standard Gaussian between -3/4 and 3/4.
We look up z in the standard normal table, the one that starts with 0 at z=0 and increases. That's the integral from 0 to z of the standard Gaussian.
For z=0.75 we get p=0.2734. So the probability, which is the integral from -3/4 to 3/4, is double that, 0.5468.
Answer: 55%
Answers
Answer:
48 Parts
Step-by-step explanation:
parts
In 28.8 hours, that machine make
parts
Answers
Part 3- If 6.5 is 22% of a value, what is the value? (round to the nearest tenth)
Part 4- If 6 is 33% of the value, what is the value?
Answers
48
29.5
18.18 are the four answers respectively
Answers
The 90% confidence interval will be "(0.674, 0.748)".
Given:
Sample no. of events,
- x = 293
Sample size,
- n = 412
Now,
The sample proportion will be:
→
The significance level will be:
Form the z-table,
The critical value,
Now,
The standard error will be:
=
=
and,
The margin of error,
→
Now,
The lower limit will be:
=
=
The upper limit will be:
=
=
hence,
The CI is "(0.6744, 0.748)". Thus the response above is right.
Learn more about confidence interval here:
Answer:
CI = (0.674, 0.748)
Step-by-step explanation:
The confidence interval of a proportion is:
CI = p ± SE × CV,
where p is the proportion, SE is the standard error, and CV is the critical value (either a t-score or a z-score).
We already know the proportion:
p = 293/412
p = 0.711
But we need to find the standard error and the critical value.
The standard error is:
SE = √(p (1 − p) / n)
SE = √(0.711 × (1 − 0.711) / 412)
SE = 0.0223
To find the critical value, we must first find the alpha level and the degrees of freedom.
The alpha level for a 90% confidence interval is:
α = (1 − 0.90) / 2 = 0.05
The degrees of freedom is one less than the sample size:
df = 412 − 1 = 411
Since df > 30, we can approximate this with a normal distribution.
If we look up the alpha level in a z score table or with a calculator, we find the z-score is 1.645. That's our critical value. CV = 1.645.
Now we can find the confidence interval:
CI = 0.711 ± 0.0223 * 1.645
CI = 0.711 ± 0.0367
CI = (0.674, 0.748)
So we are 90% confident that the proportion of adults connected to the internet from home is between 0.674 and 0.748.