Answer:
62
Step-by-step explanation:
1. 16/ 2
2. 4*8=32
3. 32+32=64
4. 64-2=62
Y= 16x + 2.50
Answer: k=−1,452
Step-by-step explanation:
k/22 x 22 = −66 x22
The value of 'k' can be determined by isolating 'k' in the equation. This results in k = 22 * -66, simplifying to k = -1452.
The equation conveyed in the question can be written as k/22 = -66. To find the variable k's value, we need to isolate k in the equation. This can be done by keeping the inverse operation on both sides of the equation balanced. Since k is currently divided by 22, we must multiply both sides of the equation by 22 to get k independently.
When we do this, the equation becomes k = 22 * -66. Then, solve for k by multiplying 22 and -66 together. So, kequals -1452.
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To multiply 46.93 and 1.8, you treat 1.8 as 18, perform the multiplication, and then reinsert the decimal in the right spot. After carrying out these steps, you'll arrive at the result of 84.474.
To multiply the numbers 46.93 and 1.8, you can use the standard multiplication algorithm. Start by thinking of 1.8 as 18, but remember to put the decimal back in the result. Here are the steps:
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If it creates a straight line on a graph, it is proportional
The product of Jenny's score and 6 is 72
Answer:
6x =72
Step-by-step explanation:
Let x = Jenny's score
Product means multiply, is means equals
x*6 = 72
6x =72
Answer:
6x =72
Step-by-step explanation:
3x - 5 1/2 is the expression
To adjust a quotient in a division problem, you can multiply both the dividend and divisor by the same number.
To adjust a quotient in order to solve a division problem, you can multiply both the dividend and divisor by the same number. This will not change the value of the quotient, but it will make the division easier to solve.
For example, if you have 12 ÷ 3 and you want to adjust the quotient, you can multiply both 12 and 3 by 10 to get 120 ÷ 30. The quotient remains the same, but now you can easily divide 120 by 30 to get the answer, which is 4.
In summary, adjusting a quotient involves multiplying both the dividend and divisor by the same number to simplify the division problem.
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