The square of a certain negative number is equal to 5 more than one half of the number what is the number
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Answer 1
Answer:
the square of a certain negative number is equal to 5 more than one half of that number
what is that number
let x be that number
thus x² = x/2 + 5
x² - x/2 - 5 = 0
2x² - x -10 = 0
(2x-5) (x + 2) = 0
x = 5/2 or - 2
so the number is - 2
what is that number
let x be that number
thus x² = x/2 + 5
x² - x/2 - 5 = 0
2x² - x -10 = 0
(2x-5) (x + 2) = 0
x = 5/2 or - 2
so the number is - 2
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Hello,
4x+y=11 (1)
x+y=2 (2)
(1)-(2)==>3x=9 ==>x=3 and y=2-3=-1
Sol={(3,-1)}
4x+y=11 (1)
x+y=2 (2)
(1)-(2)==>3x=9 ==>x=3 and y=2-3=-1
Sol={(3,-1)}
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area of circle= pi × radius^2
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2600 divided by 10 equals 260. every time you divide by ten you just take away a zero
2600/10 = 260/1 (take away one zero from numerator & denominator each) . . . any number over one is that number itself . . . so 2600/10 = 260 . . . you're number is 10
I don't understand it
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(a+b)(a-b) = a^2 - b^2
(1+5/6) (1-5/6) = 1^2 - (5/6)^2 = 1 - 25/36 = 36/36 - 25/36 = (36-25)/36 = 11/36
11/36 is your answer
(1+5/6) (1-5/6) = 1^2 - (5/6)^2 = 1 - 25/36 = 36/36 - 25/36 = (36-25)/36 = 11/36
11/36 is your answer
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The answer is 1/3, I just answered this on USATP.
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