You can divide any parallelogram into two matching triangles. How is this useful?i need to know this answer right now
please
Answers
Related Questions
I need help with this question
Rachel must store a few pieces of her furniture for six months. A storage unit costs $55 for the first month and $47.50 for the remaining months. How much will it cost to store her furniture?
Tiffany a commissioned sales person, earns $100 base pay plus $10 per item sold. Express her gross salary G as a function of the Number x of items sold
What is 4/12 as a unit fraction
2+2-1=x
Answers
Answer:
2+2 is 4 minus 1 is 3 quick math
Step-by-step explanation:
x=3
Answer:
3
Step-by-step explanation:
2+2 is 4-1 that’s 3 quick math
Answers
we are given
firstly, we will simplify left side
and then we can compare it with right side
so, we can distribute
we have i on both sides
so,i will get cancelled
we can also write as
now, we can compare
and we get
now, we can solve for p and q
we get
.............Answer
Answer:
For short the answer is A. p = 3 , q = 7
4.8y-6.9=3.18
Explain your thinking
Answers
4.8y= 3.18 + 6.9 (I added 6.9 to both sides)
4.8 y = 10.08 (I added 3.18 by 6.9)
y = 2.1 (I divided 4.8)
Hope this helps!!
so first you would add 6.9 to 3.18.
the equation would now look like this:
4.8y=10.08
you would then divide 4.8 by 10.08. this is the last step to getting the y varible by itself on one side of the equation and ultimately the value of y!
the equation now looks like this:
y=2.1
y=2.1 is you answer!
Good luck!
-3x + 3y = -9
-3x + y = 7
Answers
Answer:
x = 5
y = 2
Step-by-step explanation:
-3x + 3y = -9
3y = 3x - 9
Equation 1. y = x - 3
-3x + y = 7
Equation 2. y = 3x + 7
So, put number 1 equation to number 2's y :
x - 3 = 3x + 7
x -3x = 7 + 3
-2x = 10
2x = 10
x = 10/2
x = 5
And, put x, which is 5 , to the any equation to figure out the y.
This time, I'll use equation number 1.
y = 5 - 3
y = 2
Answers
For triangle ACB:
7^2=(AC)^2+(BC)^2 (1)
For triangle ACD:
(AC)^2=3^2+(CD)^2 (2)
For triangle DCB:
(BC)^2=(CD)^2+4^2 (3)
To make things simpler, we let
(AC)=x
(BC)=y
(CD)=z
Hence we have:
49=x^2+y^2 (1)
y^2=z^2+16 (2)
x^2=9+z^2 (3)
To solve for the unknown c, let us first substitute equation (2) in (1)
49=x^2+z^2+16
33=x^2+z^2 (4)
Then, we can substitute equation (3) in (4)
33=9+z^2+z^2
24=2z^2
z^2=12
z=2sqrt(3)
Thus, the length of z or (CD) is 2sqrt(3) in simplest radical form.