Answer:
this can be explained in terms of the Law of Conservation of mass because you just have to multiply the number of amount that was lost during the fire by 5
Explanation:
so if they lost 489 miles of mass from the fire, then u will have to multiply 489 by 5. 489x5=2445
They migrate only with one another.
B.
They fight only with one another.
C.
They share food only with one another.
D.
They reproduce only with one another.
Answer:
Autotrophs
Explanation:
Autotrophs make their own food, or produce food for themselves through the process of photosynthesis. Therefore, we can say that autotrophs are also producers. Some examples of producers are plants, algae, and some types of bacteria.
Answer:
The pressure of the gas is 2.11 atm.
Explanation:
From the given,
Therefore, The pressure of the gas is 2.11 atm.
Boyle's law is used to find the new pressure after the gas is compressed from 1.00 L to 0.473 L. The original pressure is 1 atm at Standard Temperature and Pressure (STP). After the compression, the new pressure is approximately 2.12 atm.
The question relates to gas laws, specifically Boyle's law, which states that the pressure of a gas is inversely proportional to its volume when the temperature and amount of gas are held constant. At Standard Temperature and Pressure (STP; 273.15 K and 1 atm), one mole of an ideal gas occupancies a volume of about 22.4 L. In this case, the initial conditions are at STP, with a gas volume of 1.00 L, equating to a pressure of 1 atm. When this volume is compressed to 473 mL (or 0.473 L), the pressure can be determined using Boyle's law, i.e., P1V1 = P2V2. After substituting the values, we can solve for the new pressure (P2) which will be approximately 2.12 atm.
#SPJ3
Answer:
3718.628 kPa.
Explanation:
where, P is the pressure of the gas in atm (P = ??? atm).
V is the volume of the gas in L (V = 2.0 L).
n is the no. of moles of the gas in mol (n = 3.0 mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = 298.0 K).
∴ P = nRT/V = (3.0 mol)(0.0821 L.atm/mol.K)(298.0 K)/(2.0 L) = 36.7 atm.
∵ 1.0 atm = 101.325 kPa.
∴ P = (36.7 atm)(101.325 kPa/1.0 atm) = 3718.628 kPa.
100 degrees C
c.
-183 degrees C
b.
-253 degrees C
d.
0 degrees C
Answer:
Explanation:
Answer:
Factors that influence flow :
Flow patterns in a fluid (gas or liquid) depend on three factors: the characteristics of the fluid, the speed of flow, and the shape of the solid surface. Three characteristics of the fluid are of special importance: viscosity, density, and compressibility. Viscosity is the amount of internal friction or resistance to flow. Water, for instance, is less viscous than honey, which explains why water flows more easily than does honey.
All gases are compressible, whereas liquids are practically incompressible; that is, they cannot be squeezed into smaller volumes. Flow patterns in compressible fluids are more complicated and difficult to study than those in incompressible ones. Fortunately for automobile designers, at speeds less than about 220 miles (350 kilometers) per hour, air can be treated as incompressible for all practical purposes. Also, for incompressible fluids, the effects of temperature changes can be neglected.