the flight of an aircraft from toronto to montrel can be modelled by he relation h=-2.5t2+200t where t is the time, in minutes, and h is the height in metre

Answers

Answer 1
Answer:

Final answer:

The equation for the aircraft's flight is a quadratic equation representing the height of the aircraft at any given time. By rearranging the equation to isolate time and applying the quadratic formula, we can find the time at which the aircraft reaches its maximum height, which in this case is 3.79 minutes.

Explanation:

The flight of an aircraft from Toronto to Montreal is modeled by the equation h = -2.5t2 + 200t where t represents time in minutes and h represents height in meters. This is fundamentally a quadratic equation which is utilized in physics to characterize motion under constant acceleration. In this case, it models the height of the aircraft at any given time.

To find the time at which the airplane's maximum height is achieved, we must solve the equation for t. By rearranging the equation, we can isolate t, yielding a quadratic equation as follows: 0 m = 0 m + (10.0 m/s) t + (2.00 m/s2) t2. This simplifies to 200 = 10t + t2.

Applying the quadratic formula, we find two solutions for t, 3.79 s and 0.54 s. The time it takes the aircraft to reach its maximum height would be the longer solution, which is 3.79 minutes in this case.

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Answer 2
Answer:

Final answer:

The question provides a quadratic equation to model the flight of an aircraft. This equation can be used to calculate the height of the aircraft at a specific time or to determine when the aircraft reaches its maximum height.

Explanation:

The question is asking about the trajectory of an aircraft as modelled by a quadratic equation, and specifically, how time influences height. The equation given is h = -2.5t²+200t. Quadratic equations are frequently used to describe the motion of objects when the acceleration is constant. This equation tells us that the height of the aircraft is dependent on the time squared and the time.

To solve for a specific time (t), we can plug the desired time into the equation to find the height of the aircraft at that time. For instance, if we want to find out the height of the aircraft 10 minutes into the flight, we would substitute t=10 into the equation, giving us h=-2.5 × (10)²+200 × (10). Simplifying this equation would provide the height of the aircraft 10 minutes into the flight.

Additionally, this equation could also be used to find the maximum height of the aircraft. The maximum height is reached when the derivative of the equation equals zero. Taking the derivative of h = -2.5t²+200t and setting it equal to zero will provide the time when the maximum height is reached.

Learn more about Quadratic Equations here:

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If f(x) = x+3/4 , what is the equation for f–1(x)?

Answers

=(x+3/4)-1 I think...makes sense doesn't it? If y=3 then y-1=3-1 Same goes for y=-3

In the decimal number .675, the 7 holds what place value

Answers

To see 7's rank we can count the number of digits after ".". 7 is the second digit and given that the first digit represents the decimals, 7 will represent the hundreths.

7 is representing the hundredth's place.

An astronaut who weighs 126lb on Earth weighs only21lb on the moon. How much would a person who weights 31lb on the moon weigh on Earth?

Answers

If his weight on Earth is 126lb and only 21lb on moon, you can divide 126/21 to see what is the ratio of those weights.
126/21=6

It means that your weight on moon will be 6 times less than on Earth.

Now we have to multiply 31lb which is weight of the person on moon by 6 to get his weight on Earth 6*31=186
On moon our mass becomes 1/6 of actual mass so if you weigh 60 kg then your mass on moon will be 10 kg..
Similarly if your mass on moon is 31 lbs then your mass on earth will be 31*6=186 lbs.
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Justin's phone had 35% battery when hegot home from school. He plugs in his
phone and the battery charges at a rate of
1.75% per minute. Write a linear equation
that models this scenario, where c
represents the charge and t represents
time.
+

Answers

Answer:

I believe 35c+1.75t=100c

Step-by-step explanation:

You mean, something like 35+1.75c=t

However I know that that's wrong instantly by looking at that

35c+1.75t=100c

This is how I would personally write it

Each child ticket for a ride costs $3, while each adult ticket costs $5. The ride collected a total of $150, and 40 tickets were sold. How many of each type of ticket were sold?A. 150 child and 40 adult
B. 24 adult and 10 child
C. 30 child and 10 adult
D. 25 child and 15 adult

Answers

The way to go about this is to think logically about the answers
A) isn't possible as 40 tickets were sold and 150 plus 40 = 190
B) is similar to above only there was less than 40 tickets sold
C) very possible
D) very possible
next step:
C) (30 x 3) + (10 x 5) = 90 + 50 = $140 (by this we should assume that the answer is D) 
D) (25 x 3) + (15 x 5) = 75 + 75 =  $150 ( yay answer is D :) )

Please help me solve this. :)

Answers

Answer:

45.) 45

46.) 2

47.) 16

48.) 8

49.) 10

50.) 11

51.) 16

52.) 6

53.) 55

54.) 14

Step-by-step explanation: