Which of the following are also major levels of classification?Choose all answers that are correct.

A.Genus

B.Species

C.Group

Answers

Answer 1
Answer: The answer is A and B.  kingdom, phylum, class, order, family, genus and species.
Answer 2
Answer:

Answer:

A and B

Explanation:

hope I helped


Related Questions

What is a convection cell 12 points
How does the law of conservation of energy relate to the processes going on in the water and in the plants?
What is the speed at which molecules or atoms move dependent on temperature and state of matter.
Explain why atoms move at different speeds depending on whether they are liquids or solids.
Which of the processes of the water cycle occur by releasing energy

Which has triple Bond C2 H4 C3 H6 and C3 H4​

Answers

Answer:  C3H4 (Propayne) have a triple bond.

Explanation:

The hydrocarbons which having triple bond are called alkyne. The general formula of alkyne is CnH2n-2. Here, n is number of carbon atoms.

In alkyne, the number of hydrogen atom is 2 less than double the number of carbon atoms.

Thus, the compound C3H4 (Propyne) have a triple bond.

Chemistry 2 Questions

Answers

Hai :3

Do you know how to find valence electrons? The amount of valence electrons that an element has depends on its group number, with an exception towards transitional elements.

For example, Oxygen is in group 16, which makes it have 6 valence electrons. Group 1 has 1, group 2 has 2, group 13 has 3, group 14 has 4, and so on.

What about transitional elements? The elements ranging from group 3 until 11 have different valence electrons because (advanced) if you look at their electron configuration, they have d orbital electrons (they can be edited), which gives them a varied valence configuration.

1. Iodine: Group 17 - 7 valence electrons                                                                          Calcium: Group 2 - 2 valence electrons                                                                              Chlorine: Group 17 - 7 valence electrons                                                                               Sodium - Group 1 - 1 valence electron                                                                           Neon - Group 18 - 8 valence electrons                                                                         Copper - Group 11  - *Copper is a transitional element!* Those within group 11 usually have either 1 or 2 electrons. Your teacher did not specify which copper he's asking, so you could say that there is Copper (I), which has 1 valence electron, and also Copper (II), which has 2 valence electrons.

Moving to your second question, to see how many electron shells an element has, you look at where they are in their period (horizontal row)

For example, oxygen is in period 2, therefore, it has two electron shells.                  Period 1 has 1, period 2 has 2, period 3 has 3, and so on.

1. 1. Iodine: Period 5 - 5 electron shells                                                            Calcium: Period 4 - 4 electron shells                                                                         Chlorine: Period 3 - 3 electron shells                                                                        Sodium - Period 3- 1 electron shells                                                                           Neon - Period 2 - 2 electron shells                                                                        Copper - Period 4  - 4 electron shells


Answer:

Do you know how to find valence electrons? The amount of valence electrons that an element has depends on its group number, with an exception towards transitional elements.

For example, Oxygen is in group 16, which makes it have 6 valence electrons. Group 1 has 1, group 2 has 2, group 13 has 3, group 14 has 4, and so on.

What about transitional elements? The elements ranging from group 3 until 11 have different valence electrons because (advanced) if you look at their electron configuration, they have d orbital electrons (they can be edited), which gives them a varied valence configuration.

1. Iodine: Group 17 - 7 valence electrons                                                                          Calcium: Group 2 - 2 valence electrons                                                                              Chlorine: Group 17 - 7 valence electrons                                                                               Sodium - Group 1 - 1 valence electron                                                                           Neon - Group 18 - 8 valence electrons                                                                         Copper - Group 11  - *Copper is a transitional element!* Those within group 11 usually have either 1 or 2 electrons. Your teacher did not specify which copper he's asking, so you could say that there is Copper (I), which has 1 valence electron, and also Copper (II), which has 2 valence electrons.

Moving to your second question, to see how many electron shells an element has, you look at where they are in their period (horizontal row)

For example, oxygen is in period 2, therefore, it has two electron shells.                  Period 1 has 1, period 2 has 2, period 3 has 3, and so on.

1. 1. Iodine: Period 5 - 5 electron shells                                                            Calcium: Period 4 - 4 electron shells                                                                         Chlorine: Period 3 - 3 electron shells                                                                        Sodium - Period 3- 1 electron shells                                                                           Neon - Period 2 - 2 electron shells                                                                        Copper - Period 4  - 4 electron shells

Explanation:

How to I find the number of electrons in and Atom?

Answers

Look at the atomic number of an element on the periodic table which is the smaller number.
The atomic number shows the number of protons/electrons so the number of protons and electrons are the same.
Whereas the mass number of an element (the other number) is the number of protons + neutrons.

What are some important substances found in food, which promote growth and good health?

Answers

vitamins in food, such as vitamin C in oranges, excel growth spurts. acids and juices in fruits such as pomegranates also accelerate growth. organic milk and dairy provides calcium for bone strength and also accelerate growth. these are some common nutrients in foods that help growth and development. i hope this helped. 

Give two examples of chemical energy being transformed into electrical energy

Answers

battery chemicals being turned to electricity

Using enthalpies of formation, calculate H.

Answers

ΔH° = -851.5 kJ/mol given that

\begin{array}{cc}\textbf{Species}&{\bf {\Delta H_f\textdegree{}}}\n \text{Fe}_2\text{O}_3\;(s) & -824.2\;\text{kJ}\cdot\text{mol}^(-1)\n\text{Al}_2\text{O}_3\;(s) & -1675.7\;\text{kJ}\cdot\text{mol}^(-1)\end{array}

(Source: Chemistry Libretexts.)

Explanation

Refer to a thermodynamic data table for the standard enthalpy of formation for each species.

Don't be alerted if the data for Al (s) and Fe (s) are missing. Why?

  • The standard enthalpy of formation of a substance measures the ΔH required to form each mole of it from the most stable allotrope of its elements under STP.
  • Both Al (s) and Fe (s) are already the most stable form of their element under STP (note that the state symbol matters.) There's no need to form them again.

As a result, \Delta H_f\textdegree{} = 0 for both Al (s) and Fe (s).

\displaystyle \Delta H_{\text{rxn}}\textdegree{} = \text{Sum of }\Delta H\text{ for all }\textbf{Product} - \text{Sum of }\Delta H\text{ for all }\textbf{Reactant}}\n\phantom{\Delta H_{\text{rxn}}\textdegree{}} = (1* \Delta H_f\textdegree{}(\text{Al}_2\text{O}_3\;(s)) + 1* \Delta H_f\textdegree{}(\text{Al}\;(s)) \n \phantom{\Delta H_{\text{rxn}}\textdegree{}=}-(1* \Delta H_f\textdegree{}(\text{Fe}_2\text{O}_3\;(s)) + 1*\Delta H_f\textdegree{}(\text{Fe}\;(s))

\Delta H_{\text{rxn}}\textdegree{}} = (1 * (-1675.7)) - (1*(-824.2)) = -851.5\;\text{kJ}\cdot\text{mol}^(-1).

The number "1" here emphasizes that in case there are more than one mole of any species in one mole of the reaction, it will be necessary to multiply the \Delta H_f\textdegree{} of that species with its coefficient in the equation.