¹/₄ part or 3.725 kilograms
Given:
An artist builds a sculpture out of metal and wood that weighs 14.9 kilograms,
Question:
How much does the wood part of the sculpture weighs?
The Process:
From the information above, we make a diagram that matches the composition of the sculpture material.
And now, let us calculate the wood part of the sculpture weighs.
Both 4 and 14.9 are multiplied by 10.
Both the numerator and denominator are divided by 4.
Thus, the wood part of the sculpture weighs is 3.725 kilograms or ¹/₄ part.
Keywords: an artist, builds a sculpture, out of metal and wood, that weighs 14.9 kilograms, 3/4, metal, the rest is wood, how much, the wood part, of the sculpture weighs
−2(x2 − 12x − 87); x = $87
−2(x − 6)2 + 246; x = $246
−2(x − 6)2 + 246; x = $6
Answer:
, x = $6
Step-by-step explanation:
The expression to represent the store's weekly profit in dollars, where x represents the price of a new video game.
Let
We need to rewrite this quadratic function in the vertex form.
The equivalent expression that reveals the video game price that produces the highest weekly profit is
and the price is $6
Answer:
-2(x-6)^2+246; x=$6
Hope it helps!
Blair caught 9 fish, and Jay caught 18 fish out of 27 fish. By using the two equations.
Let's assume the number of fish Blair caught is represented by the variable "B". Since Jay caught 2 times as many fish as Blair, the number of fish Jay caught can be represented by the variable "J" as 2B.
According to the given information, Jay and Blair caught a total of 27 fish. We can write this as an equation:
B + J = 27
Substituting the values for J and B in terms of each other:
B + 2B = 27
Combining like terms:
3B = 27
Now, we can solve the equation for B by dividing both sides by 3:
B = 27 / 3
B = 9
So, Blair caught 9 fish.
To find the number of fish Jay caught, we substitute the value of B back into the equation:
J = 2B
J = 2(9)
J = 18
Therefore, Jay caught 18 fish. In conclusion, Blair caught 9 fish, and Jay caught 18 fish.
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Answer:
187 hope this helps!
Step-by-step explanation: