PLEASE HELP!!!
6x - 2y = 10 for y when x = 2

Answers

Answer 1

Answer: 6(2)-2y=10
12-2y=10
-12 -12
-2y=-2
divide by -2
y=1
the answer is y equals 1

Related Questions

How do you change 26.25% into a number
Seventy-five percent of what number is 33.75?A.144B.25.3125C.45D.27
PLEASE HELP I GIVE THANKS
Jackie buys a basket for $6, 2 pounds of apples for $3.50 per pound, and 2 pounds of oranges for $3.50 each per pound. The tax for the whole purchase is $1.
Find the reciprocal. show that the product of the mixed number and its reciprocal is 1.1, 10 1/2 2, 6 3/7 3, 2 8/9 4, 15 1/4 5, 9 2/3 6, 7 5/8

The horsepower , H(s), required for a racecar to overcome wind resistance is given by the function : H(s) = 0.003s^2+0.07s-0.027 , where (s) is the speed of the car in miles per hours. What is the average rate of change in horsepower per unit speed if the race car increases in speed from 80 mph to 100 mph . A 1.64 B. 0.61 C. 12.2 D. 20.0

Answers

The average rate of change in horsepower per unit speed if the race car increases in speed from 80 mph to 100 mph is 0.61

The function of the horsepower is given as:

$\mathbf{H(s) = 0.003s^2 + 0.07s - 0.027}$

The average rate of change is calculated using:

$\mathbf{A(s) =(H(b) - H(a))/(b - a)}$

Substitute 80 and 100 for a and b, respectively

$\mathbf{A(s) =(H(100) - H(80))/(100 - 80)}$

$\mathbf{A(s) =(H(100) - H(80))/(20)}$

Calculate H(100) and H(80)

$\mathbf{H(80) =0.003 * 80^2 + 0.07 * 80 - 0.027 = 24.773}$

$\mathbf{H(100) =0.003 * 100^2 + 0.07 * 100 - 0.027 = 36.973}$

So, we have:

$\mathbf{A(s) =(H(100) - H(80))/(20)}$

$\mathbf{A(s) = (36.973 - 24.773)/(20)}$

$\mathbf{A(s) = (12.2)/(20)}$

$\mathbf{A(s) = 0.61}$

Hence, the average rate of change in horsepower per unit speed is 0.61

Read more about average rate of change at:

brainly.com/question/23715190

Average rate of change = [H(100) - H(80)] / (100 - 80)
H(100) = 0.003(100)^2 + 0.07(100) - 0.027 = 0.003(10000) + 0.07(100) - 0.027 = 30 + 7 - 0.027 = 36.973

H(80) = 0.003(80)^2 + 0.07(80) - 0.027 = 0.003(6400) + 0.07(80) - 0.027 = 19.2 + 5.6 - 0.027 = 24.773

Average rate of change = (36.973 - 24.773)/(100 - 80) = 12.2/20 = 0.61

Answer: B

a committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions.

Answers

Answer:

$(1)/(990)$

Step-by-step explanation:

The full question:

"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions?"

The permutation of choosing 3 members from a group of 11 would be:

P(n,r) = $(n!)/((n-r)!)$

Where n would be the total [in this case n is 11] & r would be 3

Which is:

P(11,3) = $(11!)/((11-3)!)=(11!)/(8!)=11*10*9=990$

So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:

1/990

What is 1 and 1/2 minus 7/8

Answers

Convert 1 and 1/2 to eights to make it easier to subtract. 1 4/8 add 1 to 4/8
12/8 then subtract that by 7/8 straight across the numerator. That then equals 5/8

You would find a common denominator 8. 1 and1/2 would be converted into 1 and4/8. 1 and 4/8 minus 7/8 equals 5/8

The distance of planet Mercury from the Sun is approximately 5.8 ⋅ 107 kilometers, and the distance of planet Venus from the Sun is 1.1 ⋅ 108 kilometers. About how many more kilometers is the distance of Venus from the Sun than the distance of Mercury from the Sun?

Answers

Answer: $5.2\cdot10^7\ km$

Step-by-step explanation:

Given: The approx distance of planet Mercury from the Sun $=5.8\cdot10^7\ km=58,000,000\ km$

The distance of planet Venus from the Sun $=1.1\cdot10^8\ km=110,000,000\ km$

We can see the

The difference distance of planet Venus from the Sun is more than the distance of planet Mercury from the Sun.

The difference between the distance = $110,000,000-58,000,000=52,000,000=5.2\cdot10^7\ km$

Hence, the distance of Venus from the Sun is $5.2\cdot10^7\ km$ more than the distance of Mercury from the Sun.

mercury : 5.8 • 107 = 620.6
Venus : 1.1 • 108 =118.8

620.6 - 118.8 = 501.8

so Venus is about 501.8 kilometers from then sun then mercury

Justin had $24 to buy a gift card for his cousin Julie and he found a gift for $22 with 5% sales tax is added on will Justin have enough money to buy the gift for Julie and if so how much will he pay