Expression A: 3 × (55 + 21)
Expression B: 3 × (22 1/2 + 21)
B.
Expression A: (75 + 23)
Expression B: (75 + 23) × 2
C.
Expression A: (44 + 32) × 8
Expression B: (44 + 32) × 4
D.
Expression A: (3 × 55) + 42
Expression B: (3 × 55) + 21
Answer:
C
Step-by-step explanation:
Answer:
The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.
Step-by-step explanation:
Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.
But,
<P = 048°
<Q = -
= 0
Sum of angles in a triangle =
<P + <Q + <S =
048° + 0 + <S =
+ <S =
<S = -
=
<S =
Applying the Sine rule,
= =
=
=
=
⇒ y =
= 12.703
y = 12.70 km
=
=
=
⇒ x =
= 10.0475
x = 10.05 km
Thus,
the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.
Convert the total length of the pipe from feet to inches.
1 foot = 12 inches.
8 feet x 12 inches = 96 total inches.
96 inches - 85 inches = 11 inches are left over.
After converting the length of an 8-foot copper pipe to inches, we find it is 96 inches long. Ralph used 85 inches of the pipe, leaving 11 inches of the copper pipe leftover.
Ralph bought an 8-foot long copper pipe. Initially, we need to convert the length of the pipe from feet to inches since the part used is given in inches. 1 foot equals 12 inches, so an 8-foot pipe is 8 * 12 = 96 inches long. Ralph used 85 inches of the pipe. So, to find out how much is left over, we subtract the amount used from the total length of the pipe: 96 inches - 85 inches = 11 inches. Therefore, Ralph has 11 inches of copper pipe left over.
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