Use elimination method to solve
5x+y=-10
7x-3y=-36
Answers
Let's multiply the first equation by 3. (As you can see y's coefficient in the first one is 1 and in the second one is -3 , we will multiply the first equation by 3 so when we add the equations their sum will be 0)
Now let's add this new equation and our second equation.
We found x=-3
Now let's plug x's value in one of the equations to find y's value.
So we found y=5
Solution ;
(-3, 5)
Related Questions
Which of the following is an infinite set?the set of lessons in this course the set of even numbers from 0 to 10 10 billion the set of integers the null set none of the above
The scale factor, k, is 2. How does the size of the image relate to the pre-image?
Write the quadratic equation in standard form. What is the value of b 2 - 4ac?1 = 2x 2 + 7x
Jordan can ride his bike 24 miles in 2 hours. How many miles can he ride his bike in 5 hours?
Answers
Answer:
$35
Step-by-step explanation:
If $21 is 60% of the original price, then the original price is ...
21 = 0.60p
21/0.60 = p = 35
The original price is $35.00.
Answer:
$35
Step-by-step explanation:
If $21 is 60% of the original price, then the original price is ...
21 = 0.60p
21/0.60 = p = 35
The original price is $35.00. , hope it helps i answered last time but was deleted
Answers
Point A (-3.0,-5.4)
Point B (-3.0,5.4)
reflection across y-axis ⇒ (a,b) reflected (-a,b)
reflection across x-axis ⇒ (a,b) reflected (a,-b)
reflection across the origin ⇒ (a,b) reflected (-a,-b)
reflection on y = x ⇒ (a,b) reflected (b,a)
Point B is a reflection of Point A across the x-axis.
Answer:
X- axis
Step-by-step explanation:
Answers
5 for x
f(5)=4(5)-2
f(5)=20-2
f(5)=18
she nees 18
she has 12
18-12=6
she needs $6 more
Answers
When you flip a fair coin, there is always a 50% chance of heads, and a 50% chance of tails. Not sure the rest of info is relevant here
Final answer:
Simulated coin tossing uses random numbers, where 0-4 and 5-9 represent heads and tails respectively. The theoretical probability of getting tails is 0.5, but empirical probabilities can differ. This discrepancy, assumed to reduce with more trials, is accounted for by the Law of Large Numbers.
Explanation:
In the context of the provided problem, you are attempting to simulate tossing a coin 20 times using a system of random numbers, where you've assigned 0-4 to represent heads and 5-9 to represent tails. Theoretically, in a fair coin toss, there's a 50% chance (0.5 probability) of getting either heads or tails.
However, experimental or empirical probability may not always align with this theoretical likelihood, especially in smaller samples. This discrepancy is due to randomness and doesn't necessarily imply the coin or system is biased. Over many trials, the relative frequency of getting tails should approach the theoretical probability, according to the law of large numbers.
To calculate the empirical probability of getting tails in your simulation, you would tally up the total number of 'tails' results (numbers 5-9) from your 20 trials, then divide that count by the total number of trials (20). So, if you get 12 'tails' results, your empirical probability would be 12/20 = 0.6.
Learn more about probability here:
#SPJ3
Enter the least whole number of hours the student needs to work in order to earn at least $200
Answers
Answer: 7.50 h ≥200
She needs to work 27 hours to earn at least $200.
Step-by-step explanation:
Hi, to write the inequality we have to analyze the information given:
- Earnings per hour : $7.50
- Hours : h
- She wants to earn at least $200.
So, she earns $7.50 per hour, the expression that represents the statement is $7.50h.
She wants to earn at least $200, "at least" means more or equal (≥200).
Mathematically speaking:
- $7.50 h ≥200
This is the inequality that represents all of the possible numbers of hours (h) the student could work to meet her goal.
For the second part we simply solve the inequation:
7.50 h ≥200
h ≥200/7.50
h ≥ 26.67
Rounded to the nearest whole number:
h ≥ 27
She needs to work 27 hours to earn at least $200.
7.5h≤200
thus
h≤80/3
writing in whole numbers we shall have:
h≤27
Answers
Answer:
First, let's simplify both sums by combining like terms:
3x + 5y - 2 + 2x - 3y + 1 = 5x + 2y - 1
4x - 8y + 3 - 5x + 6y + 7 = -x - 2y + 10
Now we can subtract the second sum from the first:
(5x + 2y - 1) - (-x - 2y + 10) = 5x + 2y - 1 + x + 2y - 10
Simplifying this expression, we get: 6x + 4y - 11