How do you factor x squared plus 3x

Answers

Answer 1

Answer: $x^2 + 3x = x (x+3)$

Answer 2

Answer: factor the x out and you have x (x+3)

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Who know the answer to 170 times 4

Lines g and h are parallel and m 1 = 45°. What is m 8?

Question 7 options:

45°

65°

115°

135°
Save

Answers

Answer:

$m<8=45\°$

Step-by-step explanation:

we know that

If the lines g and h are parallel

then

$m<8=m<1$ -----> by alternate exterior angles

see the attached figure to better understand the problem

we have that

$m<1=45\°$

therefore

$m<8=45\°$

parallel means m1 = m2
so m2=45

The average reading score on a certain test is given by y=0.150x +255.34 where x is the number of years past 1970 . In what year would the average reading score be 259.24 if this model was accurate

Answers

Answer:

The average was 259.24 in 1996.

Step-by-step explanation:

In order to find the year that the average, "y", is 259.24 we need to apply this value on the given expression, as done below:

$259.24 = 0.15*x + 255.34\n0.15*x = 259.24 - 255.34\n0.15*x =3.9\nx = (3.9)/(0.15)\nx = 26$

The average was 259.24 after 26 years, therefore it was in 1996.

A savings account earns simple interest at a rate of 6% per year. Last year the account earned $10.86 in interest. What was the balance in the account at the beginning of last year?

Answers

Answer:

The balance in the account at the beginning of last year was $181.

Step-by-step explanation:

Consider the provided information.

A savings account earns simple interest at a rate of 6% per year.

6% can be written as: 6/100=0.06

Last year the account earned $10.86 in interest.

Let the amount invested is represented by x.

$0.06* x=10.86$

$x=(10.86)/(0.06)$

$x=(1086)/(6)$

$x=181$

Hence, the balance in the account at the beginning of last year was $181.

In this case, you have to find out the number whose 6% is 10.86.

So, Let the number be x.

x * 6/100 = 10.86

x * 6 = 1086

x = 181.

So, the account balance at the beginning of last year was $181.

Did you understand?

How do you Solve 5(x+1)=3x+12?

Answers

Expand
5x+5=3x+12
Subtract 5 from both sides
5x=3x+12−5
Simplify 3x+12−5 to 3x+7
5x=3x+7
Subtract 3x from both sides
5x−3x=7
Simplify 5x−3x to 2x
2x=7
Divide both sides by 2
x=7/2

Expand
5x+5=3x+12x=7/2

the nth term of a sequence is fine by the expression 5-3n write down the first two terms of this sequence

Answers

$a_1=5-3\cdot1=5-3=2\na_2=5-3\cdot2=5-6=-1\n$

AA, BBB, and CCC are collinear, and BBB is between AAA and CCC. The ratio of ABABA, B to BCBCB, C is 1:21:21, colon, 2. If AAA is at (7,-1)(7,−1)left parenthesis, 7, comma, minus, 1, right parenthesis and BBB is at (2,1)(2,1)left parenthesis, 2, comma, 1, right parenthesis, what are the coordinates of point CCC?

Answers

Answer:

The coordinates of point C are (-8,5).

Step-by-step explanation:

It is given that A, B and C collinear and B is between A and C.

The ratio of AB to BC is 1:2. It means Point divided the line segments AC in 1:2.

Section formula:

$((mx_2+nx_1)/(m+n),(my_2+ny_1)/(m+n))$

The given points are A(7,-1) and B(2,1).

Let the coordinates of C are (a,b).

Using section formula the coordinates of B are

$B=(((1)(a)+(2)(7))/(1+2),((1)(b)+(2)(-1))/(1+2))$

$B=((a+14)/(3),(b-2)/(3))$

We know that point B(2,1).

$(2,1)=((a+14)/(3),(b-2)/(3))$

On comparing both sides we get

$2=(a+14)/(3)$

$6=a+14$

$6-14=a$

$-8=a$

The value of a is -8.

$1=(b-2)/(3)$

$3=b-2$

$3+2=b$

$5=b$

The value of b is 5.

Therefore, the coordinates of point C are (-8,5).

The coordinates of the pointC such that pointsA and B are (7, -1) and (2, 1) and the ratioAB to BC is 1 : 2 is (-8, 5).

How to determine the location of a point within a line segment

According to the Euclidean geometry, a line is formed by two points on a plane and three points are collinear if all the three points go through a single line.

By definitions of vector and ratio we derive an expression to determine the coordinates of the point B:

$\overrightarrow{AB} = (1)/(1+2)\cdot \overrightarrow{AC}$

$\vec B - \vec A = (1)/(3)\cdot \vec C -(1)/(3)\cdot \vec A$

$(1)/(3)\cdot \vec C = \vec B - (2)/(3)\cdot \vec A$

$\vec C = 3 \cdot \vec B - 2\cdot \vec A$

If we know that A(x,y) = (7, -1) and B(x,y) = (2, 1), then the coordinates of point C is:

C(x, y) = 3 · (2, 1) - 2 · (7, -1)

C(x, y) = (6, 3) + (- 14, 2)

C(x,y) = (- 8, 5)

The coordinates of the pointC such that pointsA and B are (7, -1) and (2, 1) and the ratioAB to BC is 1 : 2 is (-8, 5).

Remark

The statement is poorly formatted and reports mistakes. Correct form is shown below:

A, B and C are collinear and B is between A and C. The ratio of AB to BC is 1 : 2. If A is A(x, y) = (7, -1) and B(x, y) = (2, 1), what are the coordinates of point C?

To learn more on line segments, we kindly invite to check this verified question: brainly.com/question/25727583

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