B. 0 K
C. 41 K
D. 278 K
Answer : The correct option is, (D) 278 K
Explanation :
We are given temperature .
Now the conversion factor used for the temperature is,
where, K is kelvin and is Celsius.
Now put the value of temperature, we get
Therefore, the temperature 278 K is equal to the
Importanceofozonelayer:
Explanation:
Formationofozonelayer:ozone at the higher level of the atmosphere is a product of UV radiations acting on oxygen O2 molecule. The higher energy UV radiations split apart some molecular oxygen( O2) into free oxygen (O) atoms.
Depletionodozonelayer:The amount of ozone in the atmosphere began to drop sharply in the 1980's . This decrease has been linked to synthetic chemicals like cholorofluorocarbons ( CFC's ) which are used as refrigerants and in fire extinguishers.
Answer:
1.15 * 10^(-5) Tm²
Explanation:
Parameters given:
Magnitude of magnetic field, B = 5.7 * 10^(-5) T
Angle of magnetic field to the horizontal plane = 73°
Dimension of the desk = 81 cm × 85 cm
Area of desk, A = 6885 cm² = 0.6885 m²
The magnitude of the Magnetic Flux, |Φ|, is given as:
|Φ| = |B * A * cosθ|
Where θ = angle of the Magnetic field to the normal of the desk = 90 - 73 = 17°
Therefore, the magnitude of the Magnetic Flux will be:
|Φ| = |5.7 * 10^(-5) * 0.6885 * cos17|
|Φ| = 3.75 * 10^(-5) Tm²
When the magnitude of the magnetic flux through the top of a desk at this location is =
Parameters as per the question given:
Then The Magnitude of the magnetic field,
Then, The Angle of the magnetic field to the horizontalplane = 73°
After that, The Dimension of the desk = is 81 cm × 85 cm
Now, The Area of desk, A = 6885 cm² = 0.6885 m²
When The magnitude of the Magnetic Flux, |Φ|, is given as:
Then, |Φ| = |B * A * cosθ|
Where θ is = angle of the Magnetic field to the normal of the desk = 90 - 73 = 17°
Thus, the magnitude of the Magnetic Flux will be:
|Φ| =
|Φ| =
Find more information about Parameters here:
increase by a factor of 4
decrease by a factor of 2
decrease by a factor of 4
Answer:
Increase by a factor of 4.
Explanation:
The acceleration of a car moving with speed v in a circle of radius R is given by:
Now if we double the speed in the equation above, it becomes
. Thus:
Therefore the acceleration is increased by a factor of 4.