Simplify the expression using the order of operations.
(3-5) * -| -22 - 52 * 4|
Answers
176 + 208
384
this will be your answer
i hope this help
-2 × |-22 - 208|
-2 × |-230|
-2 × 230
-460
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PLZ HELP ASAP>>>>>>>Select all that apply. Which of these polygons is not formed by the cross-section created when a plane intersects a cube? Select all that are possible. -square -circle -pentagon -trapezoid -triangle -rectangle
Answers
Answer:
The cord is 9.6 cm away from the centre of the circle.
Step-by-step explanation:
See The Image First
The image below shows a picture of everything that’s given, labeled, and drawn in the circle.
Description of the Picture:
You can use the Pythagorean to find the what the distance (the length b) the cord is from the center. You can use the radius as the hypotenuse. The radius is half of the diameter, and the diameter is 25. So the radius is 12.5, which means that 12.5 is the hypotenuse of the triangle (also known as side c). The whole length of the cord is 16cm long, and we can use half of the cord, which is 8cm, for the triangle. So we know two sides already: the hypotenuse (the radius) and the length a of the triangle (half of the length of the cord).
To Solve (variables a, b, and c, are in italics so you don’t get confused):
⇒ Use the formula of the Pythagorean Theorem (), where b is the length of the distance from the cord to the centre of the circle (what we need to find out), a is the length of the side of the triangle (half of the cord size – 8cm), and c is the hypotenuse (the radius – 12.5cm). So plug the given values of b and c into the formula:
⇒ Solve for a by simplify:
⇒ Subtract 64 from both sides:
⇒ Find the square root of both sides to get a by itself:
⇒ Simplify to get:
which convert’s to
round the answer to the nearest tenth is
Answer: The cord is 9.6 cm away from the centre of the circle.
I hope you understand and that this helps with your question! :)
x + 2 = ±2
x + 2 = ±8
x + 2 = ±16
Answers
abs (x+2) = 2
⇒ x+2 = ±2.
The final answer is x + 2 = ±2.
Hope this helps~
The square root of (x + 2)² is (x + 2) .
The square roots of 4 are +2 and -2 .
So the resulting equation was x + 2 = ± 2 .
From there, it was pretty easy for Theo to find the solutions
to the original equation . . .
If (x + 2) = +2 , then x = 0 .
If (x + 2) = -2 , then x = -4 .
b 0
c –4
d +8
2. The Salton Sink in California is approximately 215 feet below sea level. Which of the following best describes the location of the Salton Sink as it relates to sea level?
a –215
b 0
c +215
d +2150
Answers
We need to find the best way to represent the numbers.
The score will be best represented by
The depth of the Salton Sink will be best described as .
under par means that it took
less strokes than the par of the course to complete the course.
This represented by
The negative sign comes first.
If the score is over par then it took
more strikes than the par of the course.
This score will be best represented by
Let, us take the surface sea level as .
So, the depth below the sea level will be negative and above it will be positive.
Hence, the depth of the Salton Sink will be best described as .
Learn more:
Answers
Answer:
DNE.) f(x, y) = x³y + 24x²-
Step-by-step explanation:
Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software, graph the function with a domain and viewpoint that reveal all the important aspects of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enterDNE.) f(x, y) = x³y + 24x²- 8y local maximum value(s) local minimum value(s). saddle point(s) (x, y, ) =
Answers
Answer:
a. |x - 1.5| < 0.125
b. -0.125 < x - 1.5 < 0.125
c. 1.375 < x < 1.625
d. Bolt has to be greater than 1.375 inches and less than 1.625 inches to be within the margin of error of 0.125 inches.
e. One acceptable length for a bolt is 1.4 inches.
f. One non-acceptable length for a bold is 1.7 inches.
Step-by-step explanation:
Solve for x:
-0.125 < x - 1.5 < 0.125
-0.125 < x - 1.5 and x - 1.5 < 0.125
1.375 < x x < 1.625
Write this as: 1.375 < x < 1.625
Algebra