350 - (110 - 30) ÷ 2
[350 - (110 - 30) ÷ 2]
[350 - (110 - 30)] ÷ 2
The expression used to find the amount Maxwell still owes on the skis is [350 - (110 + 30) ÷ 2]
An algebraic expression (or) a variable expression is a combination of terms by the operations such as addition, subtraction, multiplication, division, etc.
Given that, Maxwell bought a new pair of skis for $350. He put $110 down and received a students discount of $30. His mother gave him 1/2 of the balance for his birthday,
We need to find the expression that can be used to find the amount Maxwell still owes on the skis,
So, the total amount of skis = $350, he put down $110 also got $30 discount,
So, the amount = 350 - (110+30) also, his mother gave him 1/2 of the balance for his birthday.
So, the final amount is 350 - (110 + 30) ÷ 2
Hence, the expression used to find the amount Maxwell still owes on the skis is [350 - (110 + 30) ÷ 2]
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Answer:
Maxwell bought a new pair of skis for $350. He put $110 down and received a students discount of $30. His mother gave him 1/2 of the balance for his birthday. Which of these expressions could be used to find the amount Maxwell still owes on the skis?
PART A: At a certain number of visits, both plans will cost the same. At that number, how much will both plans cost, in dollars?
PART B: Which plan is more expensive at the 10th visit?
Write the number of the plan in the box.
After 15 number of visits, both plans cost $55 and at the 10th visit, plan 2 is more expensive than plan 1.
Arithmetic sequence is a sequence of numbers where the numbers are arranged ion a definite order such that the difference of two consecutive numbers is a constant. This constant of difference is called common difference which is commonly denoted by the letter 'd'.
Part A :
From the table, we can clearly express both plans as Arithmetic sequence.
Plan 1 : First term, a = 27 and common difference, d = 2
Plan 2 : First term, a = 41 and common difference, d = 1
Let n be the number of visits that both plans costs the same.
27 + 2(n - 1) = 41 + (n - 1)
27 + 2n - 2 = 41 + n - 1
2n + 25 = n + 40
n = 15
Cost = 41 + (15 - 1) = $55
Part B :
We have to find the 10th term.
For plan 1 :
Cost at 10th visit = 27 + 2(10 - 1) = $45
For plan 2 :
Cost at 10th visit = 41 + (10 - 1) = $50
The plan 2 is more expensive at the 10th visit.
Hence at the 10th visit, plan 2 is more expensive.
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Step-by-step explanation:
From the looks of it, Plan A is 25 + 2x and plan B is 40 + x.
Part A:
25 + 2x = 40 + x
x = 15
plug in any: 40 + 15 = $55
Part B:
Plan A = $45
Plan B = $50
Plan B is $5 more expensive.