Jane has $10 more than Bill, Bill has $17 more than Tricia, and Tricia has $21 more than Steve. If the total amount of all their money is $135, how much money does each have?
Answers
Jane has $55, Bill has $45, Tricia has $28, and Steve has $7.
Given that
Jane has $10 more than Bill, Bill has $17 more than Tricia, and Tricia has $21 more than Steve.
If the total amount of all their money is $135.
We have to determine
How much money does each have?
According to the question
Let the amount Steve be x,
The total amount Jane has is (10 +17+21+x)
The total amount Bill has is (17+21+x)
The total amount Tricia has is (21+x)
Then,
The total amount of all money = Jane money + Bill money + Tricia money + Steve money
The Steve has $7.
Therefore,
The total money Jane has = (10 +17+21+x) = 48 + 7 = $55
The total money Bill has = (17+21+x) = 38 +7 = $45
The total money Tricia has = (21+x) = 21 +7 = $28
Hence, Jane has $55, Bill has $45, Tricia has $28, and Steve has $7.
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Slope = (y₂ - y₁) / (x₂ - x₁) = (-4 - 5) / (0 - 2) = -9/-2 =9/2 = 4.5
Slope = 9/2 = 4.5
Hope this helps.