Send helpI have to do test corrections but I have no idea what the speed vs time graph should look like

Answers

Answer 1

Answer:

Answer:

Explanation:

at the same instant means in the same moment, same time thus A and B share the same starting time which is t=0

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The rotational speeds of four generators are listed in RPM (revolutions per minute). Arrange the generators in order based on the electric fields they create. Start with the weakest electric field and end with the strongest. Assume that the generators are identical except for their speed.Tiles 3,600 RPM 3,200 RPM 3,400 RPM 3,000 RPM Sequence < < <

What happens when a wave reflects?a. They are absorbed by the object they hit.
b. They travel through the object they hit.
c. They bend when they hit the medium.
d. They bounce off the object they hit.

Answers

they bounce off just like sun rays when they heat the atmosphere they bounce off reflection

What is the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 grams of water?

Answers

Considering the definition of percentage by mass, the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 grams of water is 6.25 %.

The percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.

In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:

$percent by mass= (mass of solute)/(mass of solution)x100$

In this case, you know:

mass of solute= 5 g
mass of water= 75 g
mass of solution= mass of solute + mass of water= 5 + 75 g= 80 g

Replacing:

$percent by mass= (5 g)/(80 g)x100$

Solving:

percent by mass= 6.25 %

Finally, the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 grams of water is 6.25 %.

Learn more:

Hello!

What the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 g of water?

We have the following data:

m1 (solute mass - iron II sulfate) = 5.0 g

m2 (solvent mass - water) = 75.0 g

m (solution mass) = m1 + m2 = 5.0 + 75.0 = 80.0 g

%m/m (percent mass by mass) = ?

We apply the data to the formula

$\%\:m/m = (m_1)/(m)*100$

$\%\:m/m = (5)/(80)*100$

$\%\:m/m = 0.0625*100$

$\boxed{\boxed{\%\:m/m = 6.25}}\Longleftarrow(solute\:in\:percent)\:\:\:\:\:\:\bf\blue{\checkmark}$

Answer:

The percent by mass of solute and mass solution of Iron II Sulfate is 6.25%

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If an element forms a 3+ ion in which group of the periodic table would you expect to find it?A. 15
B. 5
C. 13
D. 2

Answers

If an element forms a 3+ ion, one can expect to find it in group 13 of the periodic table (option C).

What is the periodic table?

Periodic table is a tabular chart of the chemical elements according to their atomic numbers so that elements with similar properties are in the same group (column).

The periodic table is made up of vertical columns called group and horizontal rows called periods.

Elements in group 13 form ions with +3 and +1 charges. The elements are as follows:

boron (B)
aluminum (Al)
gallium (Ga)
indium (In)
thallium (Tl)
nihonium (Nh)

Therefore, group 13 elements in the periodictable form +³ ions.

Learn more about periodic table at: brainly.com/question/11155928

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A company is creating a new cylindrical container to replace its original cylindrical container.´ The new container will have 4 times the volume of the original container.

´ The height of the new container will remain the same as the height of the original container.

The length of the radius of the new container will be -

f 4 times the length of the radius of the original container
g 8 times the length of the radius of the original container
h 2 times the length of the radius of the original container
j 16 times the length of the radius of the original container

Answers

The correct option is h. " 2 times the length of the radius of the original container"

Reason:
V(old) = pi r^2 h ... r = old radius
V(new) = 4pi r^2 h = pi R^2 h R = new radius
4pi r^2 h = pi R^2 h ... pi and h cancel
4r^2 = R^2
R = 2r

Which does more work, a force of 500 N moving through 10 m or a force of 100 N moving through 40 m?

Answers

Explanation:

To determine which force does more work, we can calculate the work done by each force using the formula:

Work = Force × Distance

For the first scenario:

Work = 500 N × 10 m = 5000 N·m

For the second scenario:

Work = 100 N × 40 m = 4000 N·m

Therefore, the force of 500 N moving through 10 m does more work, with a total of 5000 N·m.

(show your work)What is the net force on the box shown below?
30 N
60 N
20 N
30
60 20
< Square >

Answers

Answer:

I don't do physics , I'm sorry can't help you

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