Answer:
4,443,000,000 or 4.443 * 10^9 km.
Step-by-step explanation:
Neptune's distance from the sun = 4.5 * 10^9
= 4,500,000,000 km.
The required difference is
4,500,000,000 - 57,000,000
= 4,443,000,000 or 4.443 * 10^9.
The difference in distance from the sun between Mercury and Neptune is approximately 4,443,000,000 kilometers.
To find the difference in distance between Mercury and Neptune from the sun, we first need to understand that these distances are given in kilometers (km). Mercury is roughly 57,000,000 km from the sun, and Neptune is approximately 4.5 x 10 to the 9th power km from the sun. The 9th power, or exponent, denotes how many times a number (in this case, 10) is used in a multiplication. Hence, Neptune's distance from the sun is 4.5 x 10^9 km, or 4,500,000,000 km. To get the difference, we subtract Mercury's distance from Neptune's i.e., 4,500,000,000 km - 57,000,000 km = 4,443,000,000 km. So, the difference in distance from the sun between Mercury and Neptune is approximately 4,443,000,000 km.
#SPJ2
I think its 625, deeply sorry if it is not.
Answer:
$600
Step-by-step explanation:
Answer: y=1/2x+3. (could i have brainliest award please. I need it for virtuoso rank)
Step-by-step explanation:
We know that it is parallel to the line y=1/2x+3/2
So the slope of the line we are trying to find is 1/2
So we have y=1/2x+b.
We know that is passes through (-2,2)
So we sub it in into the equation to get
2=1/2(-2)+b.
Solving gets 2=-1+b so b=3
So the equation of the line is y=1/2x+3
Answer:
3 bytes
Step-by-step explanation:
mhm cause yes ueyeysyssdyd
Answer:
3 bytes
Step-by-step explanation:
A. 3i-4j-2k
B. -14i-9j-4k
C. 5i +3j -4k
D. -4i -14j -9k
Find v x w if v=-3i-4j-8k & w=2i+6j+4k.
A. 12i -2j +3k
B. 8i +12j +32k
C. 32i -4j -10k
D. 10 i -8j +3k
Find the cross product <-6, 7, 2> x <8, 5, -3>. Is the resulting vector perpendicular to the given vectors?
A. <-31,-2,-86>;yes
B. <-37,-2,0>; no
C. <0,-86,-37>; yes
D. <-37, 0, -80>;no
The average rate of change of f(t) from t = 2 to t = 6 is ______ thousand owners per year.
Answer:
1.5 thousand owners per year.
Step-by-step explanation:
Number of car owners is represented by the function as
f(t) = 0.25t² - 0.5t + 3.5
Where 't' is time in years.
Now we have to find the rate of change of f(t) from t = 2 to t = 6
or
f(6) = 0.25 × 36 - 0.5 × 6 + 3.5
= 9 - 3 + 3.5
= 9.5
f(2) = 0.25 × 4 - 0.5 × 2 + 3.5
= 1 - 1 + 3.5
= 3.5
Now average rate of change =
= 1.5 thousand owners per year.