A ball is projected vertically upwards from the top of a tower 60 meters high with a velocity of 30m/s.what is the maximum height above the ground level? How long does it take to reach the ground?

Answer:

3.06 seconds

Explanation:

To find the maximum height above the ground level, we can use the kinematic equation for vertical motion. The equation is:

h = (v^2 - u^2) / (2g)

Where:

h is the maximum height,

v is the final velocity (which is 0 when the ball reaches its highest point),

u is the initial velocity (30 m/s),

and g is the acceleration due to gravity (approximately 9.8 m/s^2).

Plugging in the values, we get:

h = (0^2 - 30^2) / (2 * 9.8)

Simplifying the equation gives us:

h = -900 / 19.6

The maximum height above the ground level is approximately -45.92 meters. Since the height cannot be negative, the maximum height is 45.92 meters.

To find the time it takes for the ball to reach the ground, we can use another kinematic equation:

t = (v - u) / g

Where:

t is the time,

v is the final velocity (which is 0 when the ball reaches the ground),

u is the initial velocity (30 m/s),

and g is the acceleration due to gravity (approximately 9.8 m/s^2).

Plugging in the values, we get:

t = (0 - 30) / 9.8

Simplifying the equation gives us:

t = -30 / 9.8

The time it takes for the ball to reach the ground is approximately -3.06 seconds. Since time cannot be negative, the ball takes approximately 3.06 seconds to reach the ground.