Answer:
c=9
Step-by-step explanation:
first we need to balance the equation out we can do this by getting rid ofa c on both sides.
c-5=4
then we need to get rid of the 5. we do this by adding it.
c=9
b. 48.91 s
c. 48.910 s
d. 48.9 s
Answer:
The time recorded as 48.9 s (option: d) is least precised as compared to other times.
Step-by-step explanation:
" Precision refers to the closeness of two or more measurements to each other" .
Since, in options a,b and c the time represented is quite close as they are precised to two or more decimal places.
but in option 'd' the time is precised to just one decimal place.
Hence, the time recorded as 48.9 s is least precised.
Hence, option D is the correct answer.
Hey there!!
Remember :- In an isosceles triangle, two angles and two sides are equal. And the total sum of all the angles in a triangle is 180 degrees.
One angle of the isosceles triangle is 28°
Let's take the other two angles as ' x '
As the total sum = 180°, let's get this into equation
28 + x + x = 180
28 + 2x = 180
2x = 180 -28
2x = 152
x = 76°
Hence, the angles in the triangle are as follows:
28° , 76° and 76°
Hope my answer helps!
The growth of the bacteria is represented by the exponential growth equation. Given the initial population, the four-fold increase, and the time interval for the increase, we can find the population after any given time by using the equation P = 200 * 4^(t/2.5).
The problem given is an example of an exponential growth problem. For these types of problems, we use the formula P = P0 * e^(kt), where P is the final population, P0 is the initial population, k is the growth rate, and t is time. However, in this case, we were given that the bacteria quadruples, meaning 'quadrupling' is not a continuous rate, so we use a slightly different form of the equation: P = P0 * (b)^(t/t0), where b is the times increase and t0 is the time interval for the b-fold increase.
Given that the initial population P0 is 200 bacteria, b is 4 because the population quadruples every 150 minutes, and time t0 is 150 minutes or 2.5 hours. We need to find the population P after t hours. Substituting these values into our equation gives us: P = 200 * 4^(t/2.5).
So, after t hours, the population of the bacteria will be given by the equation P = 200 * 4^(t/2.5).
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