Simplify the expression.1. (-7w)³

Simplify the expression.
2. (3t²) (-5+6)

Simplify the expression.
3. (6y²)³

Answers

Answer 1

Answer: (-7w)^3 = -7w * -7w * -7w = -343w^3
(3t^2)(-5 + 6) = (3t^2)(1) = 3t^2
(6y^2)^3 = 6^3 y^(2 * 3) = 216y^6

Answer 2

Answer: $1. (-7w)^3=-343 w^(3) \n 2. (3 t^(2) ) (-5 t^(6) )=-15 t^(8) \n 3. (6y^2)^3=216 y^(6)$

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PLZ HELP ME!
The problem is down below...

Answers

See this is real simple my friend.. See, the answer is 288

a Base side= 6
b Base side = 8
c Base side= 10
h Height= 12

Formula Volume of a Triangular Prism Is V = $(1)/(2) *a *c *h$

I’m dumb and need helpIs -2 a solution to x < -2? Is -2 a solution
to x < -2? Explain your answers.

Answers

Answer:

See below.

Step-by-step explanation:

x < -2 means that x is any number that is less than -2.

Is -2 less than -2? Answer: No.

A number is equal to itself. A number is not greater than itself or less than itself.

When the solution to an inequality is x < -2, the only values of x that are valid are numbers less than -2. -2 itself is not a valid solution.

Answer:

Step-by-step explanation:

Hmmm ok so yes but i can not explain it

Triangle ABC is going to be reflected over the line y = X.If A is located at (1,-7), where will A' be located?

Answers

Answer:

(-7, 1)

Step-by-step explanation:

Coordinate rules :]

Reflection over x-axis -- (x, y) -> (x, -y)

Reflection over y-axis -- (x, y) -> (-x, y)

Reflection over y = x -- (x, y) -> (y, x)

Reflection over y = -x -- (x, y) -> (-y, -x)

How do you determine whether three sets of points is collinear

Answers

I think you mean "a set of three points". What I would do is take one point, find the slope from that point to another one, and then find the slope from the same starting point to the third one. If the (absolute values of the) slopes from the same starting point to each of the others are equal, then the three points are collinear.

Step 1) Write an equation of the line determined by two of the points.

Unless the y-intercept is too hard to find, we're probably going to use slope-intercept form to accomplish this.
Slope-intercept form is written as $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x = 0)

Step 1a) We find the slope with the change in the y-coordinates of the two points (the "rise") over the change in the x-coordinates. (the "run")

Step 1b) We can use this slope to find the y-intercept, the value of y when x = 0.
We know how y changes accordinate to changes in x by the slope.
Just take one of the points of our line, see how much x needs to change to become equal to 0, and change y accordingly.

Step 2) We can take our third point and plug in its x and y values in that equation, now that we have the equation of our line filled out. If you evaluate the equation and it is true, then the point is on that line. If it's not true for those values, the point is not on the line.

Multiply a number by six and then subtract negative 10 the different is negative Forty-Four. What is the number.Thank you