B. sin 3y= 3( sin 2y)(cos y)
C. sin 4y= 2( sin 2y) ( cos 2y)
D. sin 4y= 4 ( sin 2y) ( cos 2y)
E. sin 8y= 2 ( sin 4y) (cos 2y)
To use a unit circle, you must know where the coordinates are.
For this problem it is asking you where the sin(11pi/6) is.
You look at the unit circle for 11pi/6.
From here you look at the coordinates.
The x value is the cosine and the y value is the sine.
This means that the sin of 11pi/6 is -1/2.
To find the csc or the cosecant you just find 1/sin.
To find the the sec or secant you find 1/cos.
To find the tangent or tan you find the sin/cos.
And to find the cot or cotangent you find 1/tan.
8 bottles of juice and 4 bags of chips? What would it cost to get a
bottles of juice and y bags of chips?
Total cost, 8 bottles of juice and 4 bags of chips:
Total cost, x bottles of juice and y bags of chips:
y
Answer:
$12.80
Step-by-step explanation:
The cost to get 8 bottles of juice and 4 bags of chips will be:
= 8($.105) + 4($1.10)
= $8.40 + $4.40
= $12.80
The cost for x bottles of juice and y bags of chips will be:
= (1.05 × x) + (1.10 × y)
= 1.05x + 1.10y
y=3
y=x-1
y=3x-1
Answer:
y = -1
Step-by-step explanation:
The graphed function is:
The line parallel to this has to be in the form of:
Since the line passes through the point (3, -1), its y coordinate is -1, therefore the function is:
Correct option is the first one
The equation to show the sum of two number is 160: x + y = 160.
An equation is a mathematical statement that shows that two expressions are equal.
To find two numbers that add up to 160, we can Set up an equation with two unknowns, x and y, representing the two numbers:
x + y = 160
Since there are infinitely many possible combinations of two numbers that add up to 160.
Some combinations are:
1. x = 80, y = 80
80 + 80 = 160
2. x = 50, y = 110
50 + 110 = 160
3. x = 30, y = 130
30 + 130 = 160
4. x = -20, y = 180
-20 + 180 = 160
5. x = 0, y = 160
0 + 160 = 160
These are just a few examples, and there are many other combinations of numbers that satisfy the equation x + y = 160.
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The possible area codes for different plan are .
Step-by-step explanation:
Given: In a different plan for area codes, the first digit could be any number from through, the second digit was either and the third digit could be any number except .
As mentioned in question:
Area codes are created by digits as:
first digit could be any number from through are .
Second digit are
And third digit couldbe any number except are .
Total number of area codes are .
Hence, the possible area codes are
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In a different plan for area codes, there are 140 possible codes.
In a different plan for area codes, the first digit could be any number from 4 through 8, the second digit was either 3, 4, 5, or 6, and the third digit could be any number except 2 or 5. To calculate the total number of possible area codes, we need to multiply the number of choices for each digit.
For the first digit, there are 5 choices (4, 5, 6, 7, 8).
For the second digit, there are 4 choices (3, 4, 5, 6).
For the third digit, there are 7 choices (0, 1, 3, 4, 6, 7, 8).
To find the total number of possible area codes, we multiply these choices together: 5 x 4 x 7 = 140.
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