The robot can travel approximately 295 yards per minute, after converting its speed from meters per second to yards per minute using the conversion factor.
To answer this question, we need to convert the robot's speed from meters per second to yards per minute. First, we know 1 yard is approximately equivalent to 0.9144 meters. Secondly, there are 60 seconds in a minute.
The robot moves at a speed of 4.5 meters per second, multiplying that by 60 will give us the distance in meters it can cover in a minute, which equals 270 meters.
To convert 270 meters to yards, we divide by the conversion factor which is 0.9144. Thus, the robot can travel approximately 295 yards per minute.
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To convert the speed from meters per second to yards per minute, multiply the speed in meters per second by 1.09361 (conversion factor for meters to yards) and then multiply by 60 (conversion factor for seconds to minutes).
To convert meters to yards, we need to use the conversion factor: 1 meter = 1.09361 yards. First, let's find out how many meters the robot can travel in one minute. Since there are 60 seconds in a minute, the robot can travel 4.5 x 60 = 270 meters in one minute. Now, let's convert meters to yards by multiplying the number of meters by the conversion factor: 270 x 1.09361 = 295.5687 yards. Therefore, the robot can travel approximately 295.5687 yards per minute.
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9a = 36
5a = 54
8a = 32
The standard form equation for this hyperbola, when vertices are (+-5,0) and one focus is (6,0), is x²/25 - y²/11 = 1.
In the question, we are given a hyperbola with vertices at (+-5,0) and one focus at (6,0). A hyperbola is defined by its distances from a given point to the two different foci, and its standard form equation along the x-axis can be written as
(x-h)²/a² - (y-k)²/b² = 1
, where (h, k) is the center of the hyperbola, a represents the distance from the center to each vertex, and b represents the distance from the center to each co-vertex. In this case,
h = 0
, since the center of the hyperbola is at the origin. The value of
a = 5
is the distance from the center to each vertex. Finally, the square of the distance c from the center to each focus is defined as
c² = a² + b²
, so we can find
b = sqrt(c² - a²)
. Here, c = 6, so b = sqrt(6² - 5²) = sqrt(11). Thus, the standard form equation of this hyperbola is
x²/25 - y²/11 = 1
.
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The difference between the greatest and lowest numbers in a piece of data is the range. The range of the given data set {6, 9, 9, 12, 18, 24, 24, 24, 37} is 31.
The difference between the greatest and lowest numbers in a piece of data is the range. The difference here is that the range of a set of data is determined by subtracting the sample maximum and minimum.
The range of the given data set {6, 9, 9, 12, 18, 24, 24, 24, 37} is,
37-6 = 31
Hence, The range of the given data set {6, 9, 9, 12, 18, 24, 24, 24, 37} is 31.
Learn more about Range:
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