What is the mass of the block of iron illustrated below?
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Answers

Answer 1
Answer:

Explanation:

Given that,

The dimensions of the block of iron is 2 cm, 10 cm and 5 cm

To find,

The mass of the block.

Solution,

We know that, the density of iron is, d = 7.874 g/cm³

Density, d=(m)/(V)

Where

m is mass and V is volume

Solving for m,

m=d* V

The block is in the form of a cuboid, V=lbh

So,

m=d* l* b* h\n\nm=7.874 * 2* 10* 5\n\nm=787.4\ g

Answer,

The mass of the block of iron is 787.4\ g.

Reference,

brainly.com/question/5189059

Answer 2
Answer:

Answer : 787.4 g

Explanation : With the given information; the volume of the block will be equal to = 5 cm X 10 cm X 2 cm = 100 cm^(3).

Therefore, the volume will be100 cm^(3).

but density of iron is found to be 7.874 g/cm^(3)

So, now calculating for mass; on the basis of the density formula;

which is density = mass/volume; so, mass = density X volume;

Therefore, mass will be 7.874 g X 100 = 787.4 g

mass of the iron block = 787.4 g


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What is the formula for photo synthesis

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6CO2 + 6H20 + (energy) → C6H12O6 + 6O2

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Carbon dioxide+water+energy(from light)=glucose and oxygen

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Both sides pull with unequal force

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Give the masses of the three most abundant Cl2O molecules

Answers

Mass is the quantity of matter present in a substance. The masses of the most abundant molecule of \rm Cl_(2)O are 85.9325, 87.9296, and 89.9267 amu.

What are isotopes?

Isotopes are the elements of the same species with the same atomic number but differ in atomic mass and physical properties.

% abundance and mass of chlorine are:

Cl-35 = 34.9688 amu

Cl-37 = 36.9659 amu

% abundance and mass of oxygen are:

O-16 = 15.9949 amu

O-17 = 16.9991 amu

O-18 = 17.9991 amu

O -16 is the most abundant form of the oxygen isotope and Cl -35 of chlorine.

The masses of the most abundant molecule are given as:

Cl-35, Cl-35, O-16:

34.9688 \;\rm amu + 34.9688 \;\rm amu + 15.9949 \rm \;amu  = 85.9325\;\rm  amu

Cl-35, Cl-37, O-16:

34.9688 \;\rm amu + 36.9659 \;\rm amu + 15.9949 \;\rm amu = 87.9296 \;\rm amu

Cl-37, Cl-37, O-16:

36.9659 \;\rm amu + 36.9659 \;\rm amu + 15.9949 \;\rm amu  = 89.9267 \;\rm amu

Therefore, 85.9325, 87.9296, and 89.9267 amu are the masses of the most abundant form of the molecule.

Learn more about mass here:

brainly.com/question/5137820

Chlorine has the following % abundance and mass:  

Cl-35 = 75.76 %, 34.9688 amu

Cl-37 = 24.24 %, 36.9659 amu

Oxygen has the following % abundance and mass:  

O-16 = 99.757 %, 15.9949 amu

O-17 = 0.038 %, 16.9991 amu

O-18 = 0.205 %, 17.9991 amu

Based in the % abundance O-16 is the most abundant oxygen isotope and Cl-35 is the most abundant chlorine isotope

So the most abundant molecule of Cl2O and their respective mass are as follows:  

1) Cl-35, Cl-35, O-16

Mass = 34.9688 amu + 34.9688 amu + 15.9949 amu = 85.9325 amu

2) Cl-35, Cl-37, O-16

Mass = 34.9688 amu + 36.9659 amu + 15.9949 amu = 87.9296 amu

3) Cl-37, Cl-37, O-16

Mass = 36.9659 amu + 36.9659 amu + 15.9949 amu = 89.9267 amu

 


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Answers

Answer:

F = 800 N

Explanation:

Given data:

Mass = 80 Kg

Acceleration = 10 m/s²

Force = ?

Solution:

Formula:

F = m × a

F = force

m = mass

a = acceleration

Now we will put the values in formula:

F = m × a

F = 80 kg × 10 m/s²

F = 800 kg.m/s²

kg.m/s² = N

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