Answer:
-2,7
-2,67
-1,8
1,9
2,5
Step-by-step explanation:
Answer:
Its D
Step-by-step explanation:
12 is the length of one side of cube.
What is cube?
In geometry, a cube is a three-dimensional solid object bounded by six square faces, facets or sides, with three meeting at each vertex. The cube is the only regular hexahedron and is one of the five Platonic solids. It has 6 faces, 12 edges, and 8 vertices
According to question, the volume of a cube is 1728 cubic units.
We have to find the length of the cube.
Volume= cubic units
⇒
⇒
Hence, is the length of one side of cube.
Learn more about cube here:
brainly.com/question/21270685?referrer=searchResults
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will mark brainliest
Answer:
x≠-1,1
Step-by-step explanation:
f(g(x)) is a composition where g(x) is is substituted for x in f(x).
Recall, f(x) is 2/x. So we write 2/|x|-1. This places x in the denominator and 0 cannot be in the denominator x. Any value of x that makes the denominator 0 will not be in the domain.
|x|-1=0
|x|=1
x=1,-1
The square root of 13 is approximately 3.60555127546. When rounded to the nearest tenth, this value becomes 3.6.
To find the nearest tenth of the square root of 13, you first need to calculate the square root of 13 using a calculator. The calculator will show that the square root of 13 is approximately 3.60555127546.
To round this to the nearest tenth, look at the second digit after the decimal point which is 0. If this number is 5 or larger, we round up the first digit after the decimal point, if not, we keep it as it is. In this case, the value of the second digit after the decimal point is 0, which is less than 5. Therefore, the square root of 13 rounded to the nearest tenth is 3.6.
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PIECE WISE FUNCTIONS!!
Answer: 60mph
Step-by-step explanation:
For each piece of our piecewise function, we have a different range for t, so we only use the expression that has a range that our t falls into. In the first, the range is 0 ≤ t ≤ 15, so the first expression ONLY WORKS for values of t that fit in this range (13, for example). In the third, the range is 240 ≤ t ≤ 250, so the third expression ONLY WORKS for values of t from 240 to 250 (242, for example). Our t does not fit in these ranges, so we do not use the first or third expression to find our answer.
In the second, the range is 15 < t < 240, so the second expression ONLY WORKS for values that are between 15 and 240, and our t is 18, so we use the second expression to find our answer. Our expression is just 60, so our final answer is at 18 seconds, the vehicle is going 60mph.
I hope this helps! :)