Please answer this I will give as many points as you want but I’m failing this class so I need this text to bring it up

Answers

Answer 1

Answer:

Answer:

$\textsf{The correct answer is the third one (below the one that you selected).}$

Explanation:

$\sf\n\textsf{In first option, when x = 2, y = 1 and -1. There are two y-values for one x-value}\n\textsf{so this is not a function.}$

$\textsf{In second option, there are infinite y-values for x = 3. So this is also not a}\n\textsf{function.}$

$\sf\n\textsf{In the third option, there are unique y-values for every values of x. Hence this is}\n\textsf{a function. Actually, the function shown here is a cubic function }y=x^3.$

$\textsf{In the last option, x = 1, y = 2, -2. Here also exists two y-values for a single x}\n\textsf{value. So this is also not a function.}$

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Can someone please help?

What would 0.9 go with??
2/25
23/50
14/20
90%

Answers

0.9 will go with 90% so that the answer

0.9 is equal to 90% so thats your answer

The raidus of circle p the larger circle is 7 times the radius of circle 0 the smaller circle. What is the ratio of the area of circle to the area of circle p?Your choices are: 1 to 7, 7 to 1, 49 to 1 , 1 to 49
plz explain

Answers

since we know that the radius of circle p is 7 times that of the radius of circle o we can say that radius of circle p equals 7x and the radius of circle o is x.
using the area formula we can say that area of circle p equals

Find the missing length. Leave your answers as radicals in simplest answer

Answers

45 45 90 triangle
legs are x and hypotonuse=x√2
10=furst x
10=x
hypotonuse=10√2
that hypotonuse is the leg of the other triangle
the hypotonuse is √2 times that
10√2=x of bigger triangle
hypotonuse=x√2=10√2 times √2=10*2=20

answer is 20 units

At a candy store a bag holds up to 1 pound of candy. Each jawbreaker (x) weighs 0.25 pounds and each gumball (y) weighs 0.1 pounds. Which inequality shows the solution for all combinations of the two candies that will fit in the 1-pound bag?

Answers

x - number of jawbreakers;
y - number of gumballs.
The weight of jawbreakers + gumballs must be less than or equal to 1 pound.
Inequality that shows the solution for all combinations of the two candies is:
0.25 x + 0.1 y ≤ 1

If x, y, and z are integers greater than 1, and (327)(510)(z) = (58)(914)(xy), then what is the value of x? (1) y is prime (2) x is prime

Answers

Answer:

1) 5

2) 5

Step-by-step explanation:

Data provided in the question:

(3²⁷)(5¹⁰)(z) = (5⁸)(9¹⁴)( $x^y$ )

Now,

on simplifying the above equation

⇒ (3²⁷)(5¹⁰)(z) = (5⁸)((3²)¹⁴)( $x^y$ )

⇒ (3²⁷)(5¹⁰)(z) = (5⁸)(3²⁸)( $x^y$ )

⇒ $((3^(27))/(3^(28)))((5^(10))/(5^8))z=x^y$

⇒ $((5^2)/(3))z=x^y$

⇒ $(5^2)/(3)=(x^y)/(z)$

we can say

x = 5, y = 2 and, z = 3

Now,

(1) y is prime

since, 2 is a prime number,

we can have

x = 5

2) x is prime

since 5 is also a prime number

therefore,

x = 5

Which of the following is always true?1. All trapezoids are similar.
II. All parallelograms are similar.
III. All kites are similar.
IV. All regular quadrilaterals are similar.
O l only
IV only
k
I and III only
O II and IV only
Please help quick

Answers

Answer:

Step-by-step explanation:

A trapezoid has one pair of parallel sides and a parallelogram has two pairs of parallel sides. So a parallelogram is also a trapezoid. A trapezoid is a quadrilateral with one pair of opposite sides parallel. It can have right angles (a right trapezoid), and it can have congruent sides (isosceles), but those are not required. In any isosceles trapezoid, two opposite sides (the bases) are parallel, and the two other sides (the legs) are of equal length (properties shared with the parallelogram). The diagonals are also of equal length.

A parallelogram has adjacent sides with the lengths of and . Find a pair of possible adjacent side lengths for a similar parallelogram. Explanation: Since the two parallelogram are similar, each of the corresponding sides must have the same ratio.

Not only are the corresponding angles the same size in similar polygons, but also the sides are proportional.

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