Dan left the city traveling at 87mph, while, Sally left the city going the opposite direction at a speed of 41mph. Find the time Dan traveled before the two were 113 miles apart

Answers

Answer 1

Answer:

Step-by-step explanation:

10858100817910891900

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Solve x2 + 4x − 12 = 0.A: x = 2, x = −6
B: x = −2, x = −6
C: x = 3, x = −4
D: x = −3, x = 4

Answers

x^2 + 4x - 12 = 0
(x + 6)(x - 2) = 0

x + 6 = 0 x - 2 = 0
x = -6 x = 2

Answer A: x = 2; x = -6

Answer:

x = - 6; x = 2

Step-by-step explanation:

If a caterer charges a fixed cost for preparing a dinner plus an additional cost for each person served. You know that the cost for 100 students will be $750 and the cost for 150 students will be $1050. find the caterers fixed cost and the cost per student served.

Answers

$x+100y=750 \n x+150y=1050 \n 50y=300 \n y=6 \n x=750-600=150$
The fixed cost is $150, while the per-student cost is $6.

It would be $6 per student while the fixed cost is $150

WHAT IS THE ANSWER TO 0.16PSQUARED-0.0025

Answers

$(0.16)^2-0.0025=0.0256-0.0025=0.0231$

Need help with question 5 please

Answers

Answer:

-1/6

Step-by-step explanation:

To find the slope we use

m = (y2-y1)/(x2-x1)

= (-4-8)/( 1-3)

= -12/-2

We want a line perpendicular, so we need the negative reciprocal

- (1/6)

-1/6

HELP ASAP I NEED THIS DONE.

Answers

26 - add all the sides

Solve for the roots in simplest form using the quadratic formula: 4x2+20x=-29

Answers

To solve the quadratic equation 4x^2 + 20x = -29 using the quadratic formula, we can first rearrange the equation to bring all terms to one side:

4x^2 + 20x + 29 = 0

Now we can identify the coefficients a = 4, b = 20, and c = 29 in the general quadratic equation ax^2 + bx + c = 0. Applying the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

Substituting the values for a, b, and c into the quadratic formula:

x = (-(20) ± √((20)^2 - 4(4)(29))) / (2(4))

Simplifying further:

x = (-20 ± √(400 - 464)) / 8

x = (-20 ± √(-64)) / 8

x = (-20 ± 8i) / 8

Now, we can simplify the expression:

x = -20/8 ± (8i)/8

x = -5/2 ± i

Therefore, the roots of the given quadratic equation are:

x = -5/2 + i

x = -5/2 - i

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