MATHEMATICS HIGH SCHOOL

Really confused. Need help asap

Answers

Answer 1

Answer:

Terms:

Domain - All the "x" values (horizontal)
Range - All the "y" values (vertical)

Writing in interval notation:

[] - Point is included

() - Point not included.

Domain = [8,12]

Range = [-6,-2]

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Hirva ate 5-.8 of a medium pizza.elizabeth ate 1-.4.how much pizza did they eat together

Answers

Im assuming by 5-.8, you mean 5/8ths and by 1-.4, you mean 1/4th...

x=5/8+1/4

x=5/8+2/8
x=7/8

They ate 7/8 together

What is the value of x, when -25(x - 4) = -55(x - 10)?A) x = 5
B) x = -5
C) x = 8 1/8
D) x = 15

Answers

-25(x-4)=-55(x-10)
-25x+100 = 55x-550 |+25x
100 = 80x-550 |+550
650 = 80x | /80
65/8 = x
x = 8 1/8
C

Answer:

Step-by-step explanation:

The answer is d i took the test

Find the midpoint between the points (5, 8) and (2, 7) on the coordinate plane.a) (7/2, 15/2)
b) (7/2, 15)
c) (7, 15)
d) (6, 5)

Answers

midpoint = (5+2/2 , 8+7/2)
= (7/2, 15/2)

a. (7/2, 15/2)

The vertex form of a function is g(x) = (x – 3)2 + 9. How does the graph of g(x) compare to the graph of the function f(x) = x2?

Answers

we have

$g(x)=(x-3)^(2)+9$

This is the equation of a vertical parabola with vertex at point $(3,9)$

The parabola open upward------> the vertex is a minimum

$f(x)=x^(2)$

This is the equation of a vertical parabola with vertex at point $(0,0)$

The parabola open upward------> the vertex is a minimum

the rule of the translation is

$f(x)------> g(x)$

$(x,y)-----> (x+3,y+9)$

that means

the translation is $3$ units to the right and $9$ units up

the graph of the function g(x) is the translated graphic of the function f(x) $3$ units to the right and $9$ units up

therefore

the answer is

g(x) is shifted $3$ units right and $9$ units up

in y=a(x-h)^2+k
vertex=(h,k)

f(x)=x^2,
the vertex is (0,0)
it opens up

g(x)=(x-3)^2+9
vertex is (3,9)
opens up

Which decimal is equivalent to 5/6

Answers

the answer is 0.8333.....

0.8333 or 83.333% your welcome

So, I really need help with functional notation...If anyone could help me solve these problems, I'd be extremely grateful!!Given the function G ( x ) =sqrt 2x-1 , find the value G (1), G(0), G(5), G(-4).
Given the function F ( x ) = x^2 - 3 x + 1, find the value F (-3), F(0), F(1).
Given the function H ( x ) = 3 x - 1, find the value H (2).

Answers

$g(x)=√(2x-1)$
$g(1)=√(2(1)-1)=√(2-1)=√(1)=1$
$g(0)=√(2(0)-1)=√(0-1)=√(-1)=i$
$g(5)=√(2(5)-1)=√(10-1)=√(9)=3$
$g(-4)=√(2(-4)-1)=√(-8-1)=√(-7)=i√(7)$

$f(x)=x^(2)-3x+1$
$f(-3)=-3^(2)-3(-3)+1=9-(-9)+1=19$
$f(0)=0^(2)-3(0)+1=1$
$f(1)=1^(2)-3(1)+1=-1$

$h(x)=3x-1$
$h(2)=3(2)-1=5$

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