What acceleration would engineers at Boeing calculate for the 737-900 during a typical take-off, given the plane's 78,200-kg mass and its maximum engine force of 121,000 N? A) 1.55 m/s² B) 0.98 m/s² C) 2.45 m/s² D) 0.62 m/s²

Answers

Answer 1

Answer:

Answer:

Approximately $1.55\; {\rm m\cdot s^(-2)}$ , assuming that the runway is level, and that air resistance is negligible at the start of take-off.

Explanation:

The acceleration of this aircraft can be found in the following steps:

Find the net force on this aircraft.
Divide net force by mass to find acceleration.

Assume that when the plane just started the take-off, the air resistance (drag) on this aircraft is negligible. Forces on this aircraft during takeoff would include:

Weight of the aircraft (downward),
Normal force from the ground (upward), and
Thrust (forward.)

Under the assumption that the plane is on a level runway, forces in the vertical direction would be balanced. The only unbalanced force would be thrust, which is in the horizontal direction. Hence, the net force on this aircraft would be equal to thrust.

If the engine force is at the maximum value, the thrust and the net force on the aircraft would be $121,\!000\; {\rm N}$ . Divide the net force on this aircraft by mass to find acceleration:

$\begin{aligned} a &= \frac{F_{\text{net}}}{m} \n &= \frac{121000\; {\rm N}}{78200\; {\rm kg}} \n &\approx 1.55\; {\rm m\cdot s^(-2)}\end{aligned}$ .

In other words, the acceleration of this aircraft would be no greater than approximately $1.55\; {\rm m\cdot s^(-2)}$ under the assumptions.

Answer 2

Answer:

Final answer:

The acceleration of the Boeing 737-900 during take-off, calculated using Newton's second law of motion (Force = Mass x Acceleration), is approximately 1.55 m/s².

Explanation:

The acceleration of the Boeing 737-900 during take-off can be calculated using Newton's second law of motion, which states that Acceleration = Force/Mass. In this case, the force is the maximum engine force, and the mass is the mass of the airplane. So, acceleration (a) = Force (F) / Mass (m) = 121,000 N / 78,200 kg = 1.548 m/s². Therefore, the closest answer to this calculation would be A) 1.55 m/s².

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