MATHEMATICS HIGH SCHOOL

Sabr buys a magazine and a pizza. She spends $9.75. The pizza costs twice as much as the magazine. How much does the pizza cost?​

Answers

Answer 1
Answer:

Answer:

  • The magazine costs $3.25
  • The pizza costs $6.50

Explanation:

Let's say the magazine costs \tt{\$x}. Since the pizza costs twice as much as the magazine, the pizza costs \tt{\$2x}.

Now we know that the total cost of the magazine and pizza is $9.75. So, the equation becomes:

  • \LARGE \boxed{\tt{x + 2x = 9.75}}

Combining like terms, we get:

  • \large \boxed{ \tt{3x = 9.75}}

To solve for \tt{x}, we divide both sides of the equation by 3:

  • \large \boxed{\tt{x = 3.25}}

Therefore, the pizza costs:

  • \huge \boxed{\tt{2x = 2(3.25) = 6.50}}

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Answer 2
Answer:

Answer:

pizza costs = $3.25

Step-by-step explanation:

let the cost of pizza = $x

let the cost of magazine = $y

according to the question:

x + y = 9.75              (1)

y = 2x                       (2)

by substituting the value of y from equation (2) into equation (1)

x + 2x = 9.75

3x = 9.75

x = 9.75/3 = 3.25

thus, cost of pizza = $3.25

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.
EF bisects m<EDG (given)

#1
so m<DEF = m<FEG = 88/2 = 44

#2.
if m<FED = 27 then m<GED = 27 * 2 = 54 

#3
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#9
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m<ABC = 5x+18 = 5(6) +18 = 30 + 18 = 48
hope you can read this. 

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