Answer: B
Explanation:
All of your answers look wrong
Explanation:
Hello!
Let's solve this!
An Arrhenius acid is a substance that, when dissolved, forms stainless hydrogen (H +)
An Arrhenius base is a substance that when dissolved produces oxhydryl ions (OH-).
For example:
hydrochloric acid: HCl
Nitric Acid: HNO3
An Arrhenius acid is a substance that releases hydrogen ions when dissolved in water. Examples can range from strong acids, like hydrochloric acid, to weak acids like vinegar. The concept was formulated by Svante Arrhenius, underlining the importance of hydrogen in the definition of acids.
An Arrhenius acid is specifically defined as a substance which, when dissolved in water, releases hydrogen ions (or protons). This includes strong acids like hydrochloric acid (HCl), which releases all of their hydrogen ions in solution, thereby becoming completely ionized. However, this also includes weak acids like vinegar, or acetic acid, which do not ionize completely and still leave some hydrogen ions within the compound.
These properties of acids were formulated by Svante Arrhenius in the late 19th century, underlining the importance of hydrogen in defining acids. The ability of acids to release hydrogen cations led to their definition as acid substances.
Thus, if a substance releases hydrogen ions into a solution when dissolved in water, it can be described as an Arrhenius acid.
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Answer:
hi
Explanation:
The dispersion force and the dipole force has been the attractive forces that result in the formation of bond within the molecules and result in the change in the properties of the compounds.
The dipole force is a strong force and results in a higher boiling point.
The statements regarding the forces are:
(a) For molecules with similar molecular weights, the dispersion forces become stronger as the molecules become more polarizable.
The statement is true.
(b) For the noble gases the dispersion forces decrease while the boiling points increase as you go down the column in the periodic table.
The statement is true.
(c) In terms of the total attractive forces for a given substance, dipole-dipole interactions, when present, are always greater than dispersion forces.
The statement is false.
(d) All other factors being the same, dispersion forces between linear molecules are greater than those between molecules whose shapes are nearly spherical.
The statement is true.
For more information about the dispersion force, refer to the link:
Answer:
A ,B- false
C,D- true
Explanation:
Dipole forces always lead to stronger attraction and boiling points than dispersion forces. When linear molecules are involved, they often posses greater dipole forces and higher boiling points. Linear alkanes posses higher boiling points than branched alkanes.
Answer:
I tried the lanthanide series and the alkali metals and it was wrong, I think the only other option would be the lanthanide series and the actinide series.
Sorry!!!