Jose sells all of his shares at $128.34. How much money did Jose make?OA. $192.50
OB. $207.20
C. $224.60
OD. $212.50

Answers

Answer 1
Answer:

Final answer:

To calculate how much money Jose made from selling his shares, we need to know the number of shares he sold.


Explanation:

To calculate the amount of money Jose made, we need to know the number of shares he sold. Let's say he sold x number of shares. Since he sold all of his shares at $128.34 per share, the total amount of money he made can be calculated by multiplying the price per share by the number of shares: $128.34 * x = total amount made. Without knowing the number of shares, we cannot determine the exact amount Jose made.


Learn more about Calculating profit from selling shares here:

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What is the result when the number 42 is decreased by 50%?
Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 4 right angle0,−4 in the directions parallel to and normal to the plane that makes an angle of StartFraction pi Over 3 EndFraction π 3 with the positive​ x-axis. Show that the total force is the sum of the two component forces.

The amount is 2.88 is ( percent of what price?

Answers

Answer:

Discount = Original Price x Discount %/100

Discount = 2.88 × 1/100

Discount = 2.88 x 0.01

You save = $0.03

Final Price = Original Price - Discount

Final Price = 2.88 - 0.0288

Final Price = $2.85

I am a rectangle. two of my sides are each 7 inches long. My area is 28 square inches. What is the length of each of my other two sides?

Answers

If one pair of sides is 7 inches and the area is length times width then the answer would be whatever you multiple by 7 to get 28, so it would be 4 inches for each of the other two sides.

Answer:

4

Step-by-step explanation:

The formula for a rectangle is base times height so if one side is 7 inches then you need to figure out what times seven equals 28, which would be four.

A company is considering a new manufacturing process. It knows that the rate of savings (in dollars per year) from the process will be about S(t) = 5000(t + 3), where t is the number of years the process has been in use. Find the total savings during the first year. Find the total savings during the first 5 years. The total savings during the first year is __________

Answers

Answer:

Total saving during first 5 years=$137500

Total saving during first year=$17500

Step-by-step explanation:

We are given that

Savings rate

S(t)=5000(t+3)

Total saving during first 5 years is given by

=\int_(0)^(5)5000(t+3)dt=5000[(t^2)/(2)+3t)]^(5)_(0)

Total saving during first 5 years=5000((25)/(2)+3(5))=$137500

Total saving during first year=\int_(0)^(1)5000(t+3)dt

Total saving during first year=5000[((t^2)/(2)+3t)]^(1)_(0)

Total saving during first year=5000((1)/(2)+3)=$17500

You and a friend both leave the same restaurant to drive home. You are heading directly west at 30 miles per hour and he or she is heading directly south at 40 miles per hour. After half an hour, how fast (in mph) is the distance between you changing? Do not include units in your answer.

Answers

Answer:

  50

Step-by-step explanation:

The distance between the friends is changing at the constant rate of 50 mph.

___

The equation for the distance in the westerly direction is ...

  w = 30t . . . . . miles, where t is time in hours

The equation for the distance in the southerly direction is ...

  s = 40t . . . . . miles, where t is time in hours

Then the total distance between the friends is ...

  d = √((30t)² + (40t)²) = √(2500t²) = 50t  . . . . miles, where t is time in hours

And the rate of change of distance is the derivative of this with respect to t:

  dd/dt = 50 . . . . . . miles per hour

I need help with this question

Answers

Answer:
_______________________________________________
1)  72\pi cm² / min.  ;
_______________________________________________
2)  192 \pi cm² / min.  
_______________________________________________
Explanation:
____________________________________________
     
 Area of a circle:  A = \pi r² ;

Rate of change of Area is:  da/dt = 2\pi r (dr/dt) ;

Given:  dr/dt = 3 cm / min.
______________________________________________________
 Problem 1)
____________________________________________________________
dA/dt = 2 \pi *(12 cm)*(3 cm/ min) = 72 \pi  cm² / min. ;
____________________________________________________________
 Problem 2)
____________________________________________________________
dA/dt = 2 \pi *(32 cm)*(3 cm/ min) = 192 \pi  cm² / min.
_____________________________________________________________

The third and the sixth term of a geometric progression are 24 and 64/9 respectively. Finda) the first term and common ratio
b) the sum of the first five terms​

Answers

Answer:

Ai. Common ratio = 2/3

Aii. First term = 54

B. Sum of the first five terms = 422/3

Step-by-step explanation:

From the question given above, the following data were obtained:

3rd term (T3) = 24

6Th term (T6) = 64/9

First term (a) =?

Common ratio (r) =?

Sum of the first five terms​ (S5) =?

Ai. Determination of the common ratio (r).

T3 = ar²

T3 = 24

24 = ar²....... (1)

T6 = ar⁵

T6 = 64/9

64/9 = ar⁵......... (2)

The equation are:

24 = ar²....... (1)

64/9 = ar⁵......... (2)

Divide equation 2 by equation 1.

64/9 ÷ 24 = ar⁵ / ar²

64/9 × 1/24 = r³

8/27 = r³

Take the cube root of both side

r = 3√(8/27)

r = 2/3

Thus, the common ratio is 2/3

Aii. Determination of the first term (a).

T3 = ar²

3rd term (T3) = 24

Common ratio (r) = 2/3

First term (a) =?

24 = a(2/3)²

24 = 4a/9

Cross multiply

24 × 9 = 4a

216 = 4a

Divide both side by 4

a = 216/4

a = 54

Thus, the first term (a) is 54

B. Determination of the sum of the first five terms.

Common ratio (r) = 2/3

First term (a) = 54

Number of term (n) = 5

Sum of first five terms (S5) =?

Sn = a[1 –rⁿ] / 1 – r

S5 = 54[1 – (⅔)⁵] / 1 – ⅔

S5 = 54 [1 – 32/243] / ⅓

S5 = 54 (211/243) × 3

S5 = 54 × 211/81

S5 = 6 × 211/9

S5 = 2 × 211/3

S5 = 422/3

Thus, the sum of the first five terms is 422/3