MATHEMATICS HIGH SCHOOL

-6+4y<6;(-3,-3) is it a solution?

Answers

Answer 1
Answer:

Answer: Yes.

Step-by-step explanation:

   First, we will solve the given equation for y.

       Given:

           -6 + 4y < 6

       Add 6 to both sides of the equation:

           4y < 12

       Divide both sides of the equation by 4:

           y < 3

   Then, we will confirm if the given coordinate point is within this range. We find that this is a solution.

           y < 3

           -3 < 3 ✓

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Answer question "11" please!!

Answers

5(7)^2x = 1650
7^2x = 330
2x log7 = log330
2x = log330/log7
x = (log330/log7)/2
x = 1.49

Los op vir :/ Solve for y: 3.4.1 3y+7= 4y 3.4.2 10-3y+4=8+4v-y 3.4.3 2(y+1)=10-2/3v-4)​

Answers

Step-by-step explanation: First equation: 3.4.1 3y + 7 = 4y

Subtract 3y from both sides: 3.4.1 (3y - 3y) + 7 - 3y = 4y - 3y

Simplify: 3.4.1 7 = 4y

Divide both sides by 3.4.1: 7 / 3.4.1 = 4 / 3.4.1 * y

Multiply both sides by y: 7y = 4 * 3.4.1y

Substitute 7y with LHS: 4 * 3.4.1y = 7 *  Second equation: 3.4.2 10 - 3y + 4 = 8 + 4v - y

Add 3y to both sides: 3.4.2 (10 - 3y + 4) + 3y = 8 + 4v - y + 3y

Simplify: 3.4.2 17 = 12 + 4v

Subtract 12 from both sides: 3.4.2 (17 - 12) + 12 = 4v

Divide both sides by 3.4.2: 4.2 * 5 = 4v

Multiply both sides by v: 4.2v = 4 *

-2 - 14 + 147
What is the value

Answers

The answer is 131.

-2-14 is -16
-16+147= 131

Am I correct? Please explain!

Will mark brainliest

Answers

Answer:

nr. 1 and 3 is a Dilation 2 and 4 are not Dilations

Step-by-step explanation:

Dilation is an elnargment or shink of a figure by a x(factor) that makes the SAME image but smaller or larger

A cone is placed inside a cylinder. The cone has half the radius of the cylinder, but the height of each figure is the same. The cone is tilted at an angle so its peak touches the edge of the cylinder’s base. What is the volume of the space remaining in the cylinder after the cone is placed inside it?

Answers

The volume of the cylinder is:
Vcy = π r2 h

And using the given conditions that the cone has half the radius of and same height with the cylinder, we have:
Vco = (1/3) π (r/2)2 h
Vco = π r2 h / 12

The volume of the space remaining is the difference between the two volumes. So,
Vs = Vcy - Vco
Vs = π r2 h -  π r2 h / 12
Vs = 11 π r2 h / 12

The volume of the space is 11 π r2 h / 12

Find cos theta if csc theta = square root 5

Answers

Answer:

cos theta = adjacent/hypotenuse = (2)/(√(5) )

Step-by-step explanation:

csc theta = hypotenuse/opposite = √(5) /1 (reciprocal identity)

1^2 + b^2 = √(5)^2 (pythagorean theorem)

b^2 = 5-1

b = 2

cos theta = adjacent/hypotenuse = 2/√(5) (quotient identity)
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