​​​Find the equations of the vertical asymptotes of the given rational function f(x)=(x²+9x)(x²-2x-15)

Answers

Answer 1
Answer:

To find the vertical asymptotic equations of the rational function, we must first find the points of intersection of the function with the x-axis. These points are the solutions of the equation f(x) = 0. We decompose the exponential function into the product of two expressions: f(x) = (x² + 9x)(x² - 2x - 15) Now we can set each of the expressions inside the parentheses equal to zero and solve the vertical asymptotic equations: x² + 9x = 0 or x² - 2x - 15 = 0 To solve the first equation, we can factor x out: x(x + 9) = 0 So the two vertical asymptote equations are x = 0 and x + 9 = 0 (that is, x = -9). To solve the second equation, we can use the analysis method or the quadratic formula. Using the analysis method, we can decompose the expression x² - 2x - 15 in the following form: (x - 5)(x + 3) = 0 Therefore, two vertical asymptote equations equal to x - 5 = 0 (that is, x = 5) and x + 3 = 0 (that is, x = -3). So the vertical asymptotic equations of the rational function f(x) = (x² + 9x)(x² - 2x - 15) are equal to x = 0, x = -9, x = 5 and x = -3.


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Square root of 9610 by division method​

Answers

Answer:98.03060747

Step-by-step explanation:

Square root 9610

The answer is 98.03060747

Hope it helps xD

Inequality for 3x+1>x-1

Answers

Answer:

x>-1

Step-by-step explanation:

solve this normally like a linear equation

3x + 1 >x-1

collect like terms

3x-x>-1-1

2x>-2

x>-2/2

x>-1

3 x +11 = 10 Does this problem have one, many, or no solutions?

Answers

it has just one solution and dats elimination method
one

3x+11=10
minus 11 both sides
3x=-1
divide by 3 boths ides
x=-1/3
one solution

What is the solution of the equation?-10 + sqrt x+8 = -4

Answers

D:x+8\geq0\to x\geq-8\n\n-10+√(x+8)=-4\ \ \ /+10\n\n√(x+8)=-4+10\n\n√(x+8)=6\iff x+8=36\n\nx=36-8\n\nx=28\in D

An object that starts at rest accelerates until it is moving at 247 km/h. If it takes 1.7 minutes for this change to occur what is the average acceleration in m/s? 20 PTS!

Answers

I figured out the answer Chaseashley24! The answer to your question is:

0.673 m/s²

Hope this helps!

Prove that (x^5)-(x^2)+2x +3=0 has at least one real root.Prove that x=cosx has at least one solution.

Answers

The first one is of order 5, so it has either 1, 3 or 5 real roots (unless any coefficent was complex). Proof complete :)
The other one, if it has a solution, it must be in [-1;1]. Because it only gives positive results the solution is further restricted to [0;1]. Because the cosine function is continuous and strictly decreasing on this interval, the difference of x and it's cosine will shrink up to some point within the interval where it gets to 0 (the solution) and then flips sign (the cosine gets less than the number), further decreasing until the end of the interval.

Answer:

ok no cap

Step-by-step explanation: