When 2 mol of Fe(s) reacts with Cl2(g) to form FeCl3(s) according to this equation, 799 kJ of energy is evolved. Calculate ΔrHo. A) -399.5 kJ mol^-1 B) -199.75 kJ mol^-1 C) 399.5 kJ mol^-1 D) 199.75 kJ mol^-1

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Answer 1
Answer:

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Which statement about the density of warm water is most likely correct?Warm water is more dense than cold water.
Warm water is less dense than cold water.
The density is the same for warm and cold water.
The density will sometimes be higher for warm water and other times higher for cold water.

Answers

option b. warm water is less dense than cold water.

It is due to the the effect of heat on water molecules that's why warm water tend to rise above cold ones. The molecules of the water are excited by the energy. They begin moving faster, so when they bump into one another, they bounce further away. The increase space between the fast-moving molecules decreases the density.

sodium chloride and glucose both are soluble in water but the solubility of NaCl is greater then glucose why.

Answers

The solubility of a substance in water depends on several factors, including the nature of the solute and solvent, as well as the intermolecular forces involved.

In the case of sodium chloride (NaCl) and glucose, both substances are indeed soluble in water. However, the solubility of NaCl is generally greater than that of glucose due to differences in their chemical properties.

NaCl is an ionic compound, meaning it consists of positive sodium ions (Na+) and negative chloride ions (Cl-). When NaCl is added to water, the polar water molecules surround the ions and separate them from the crystal lattice. These water molecules form favorable interactions with the charged ions through ion-dipole attractions, resulting in the dissolution of NaCl in water. These strong ion-dipole forces contribute to the high solubility of NaCl in water.

On the other hand, glucose is a covalent compound composed of carbon, hydrogen, and oxygen atoms. It does not dissociate into ions when dissolved in water. Instead, glucose molecules interact with water through weaker intermolecular forces such as hydrogen bonding and dipole-dipole interactions. While these forces allow glucose to dissolve in water, they are relatively weaker than the ion-dipole interactions in NaCl-water solution. As a result, glucose has a lower solubility compared to NaCl in water.

Therefore, the differing chemical properties of sodium chloride and glucose contribute to the higher solubility of NaCl in water compared to glucose.



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A solution can be both a. Dilute and concentrated
b. Saturated and dilute
c. Saturated and unsaturated
d. Supersaturated and saturated
e. None of these

Answers

D) Supersaturated and Saturated

Ammonia and sulfuric acid react to form ammonium sulfate. Determine the starting mass of each reactant if 20.3 g of ammonium sulfate is produced and 5.89g of sulfuric acid remains unreacted.

Answers

Answer: The mass of ammonia is 5.236 g and that of sulfuric acid is 15.064 g

Explanation:

  • Calculating the mass of ammonia:

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

Given mass of ammonium sulfate = 20.3 g

Molar mass of ammonium sulfate = 132.14 g/mol

Putting values in equation 1, we get:

\text{Moles of ammonium sulfate}=(20.3g)/(132.14g/mol)=0.154mol

The chemical equation for the reaction of ammonia and sulfuric acid follows:

2NH_3+H_2SO_4\rightarrow (NH_4)_2SO_4

As, sulfuric acid remains unreacted, which means it is an excess reagent and its starting mass cannot be determined from ammonium sulfate.

By Stoichiometry of the reaction:

1 mole of ammonium sulfate is produced by 2 moles of ammonia.

So, 0.154 moles of ammonium sulfate is produced by = (2)/(1)* 0.154=0.308mol of ammonia.

Now, calculating the mass of ammonia from equation 1, we get:

Molar mass of ammonia = 17 g/mol

Moles of ammonia = 0.308 moles

Putting values in equation 1, we get:

0.308mol=\frac{\text{Mass of ammonia}}{17g/mol}\n\n\text{Mass of ammonia}=5.236g

  • Calculating the mass of sulfuric acid

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.  

This also means that total mass on the reactant side must be equal to the total mass on the product side.

Let the mass of sulfuric acid be 'x' grams

We are given:

Mass of ammonium sulfate = 20.3 grams

Mass of ammonia = 5.236 grams

Total mass on reactant side = 5.236 + x

Total mass on product side = 20.3 g

So, by applying law of conservation of mass, we get:

5.236+x=20.3\n\nx=15.064g

Hence, the mass of ammonia is 5.236 g and that of sulfuric acid is 15.064 g

2NH₃    +    H₂SO₄     ⇒     (NH₄)₂SO₄
34.06g  :     98.08g      :      132.14g
     x               y                 20.03g

x = [20.03g*34.06g]/132.14g = 5.16g

5.16g + y = 20.03g  ⇔  from stoichiometric ratio
20.03g - 5.16g = y
y = 14,87g + 5.89g = 20.76g  
⇔ 5.89g of sulfuric(VI) acid remains unreacted

Starting mass:

mNH₃ = 5.16g
mH₂SO₄ = 20.76g

Halothane is an alkyl halide used as an inhalational general anesthetic. Which of the following could be used to reduce an alkyl halide to an alkane? Please select the correct option: LiAlH4 Zn, H+ Mg in anhydrous ether, then water All of the above

Answers

Answer:

The answer is D) All the above

Explanation:

There is a correlation between algae height and the snout-to-vent length of a group of marine iguanas in the Galapagos; as algae height increases for a given island, so does iguana length. Why would the body size of this population of iguanas correlate with algae height?Differential reproduction of larger animals is favored when adequate nutrition is supplied by larger algae.
Increased variation in animal size is favored when large plant species are present in a healthy ecosystem.
Overproduction of smaller animals is favored when algae swards are short and vice versa when algae swards are long.
Traits are exchanged between iguana and algae populations so that taller algae result in larger iguana populations

Answers

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The body size of this population of iguanas correlate with algae height because Traits are exchanged between iguana and algae populations so that taller algae result in larger iguana populations

Answer;

The correct answer would be Differential reproduction of larger animals is favored when adequate nutrition is supplied by larger algae.

The size of the food influences the size of the organism.

Due to availability of larger food or larger algae, longer iguanas tend to live and survive more.

Thus, the tend to survive and reproduce more as compared to the shorter iguanas.

Similarly, when algae or food is not available, then larger iguanas die due to malnutrition and shorter iguanas tend to survive.