To solve the quadratic equation 4x^2 + 20x = -29 using the quadratic formula, we can first rearrange the equation to bring all terms to one side:
4x^2 + 20x + 29 = 0
Now we can identify the coefficients a = 4, b = 20, and c = 29 in the general quadratic equation ax^2 + bx + c = 0. Applying the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
Substituting the values for a, b, and c into the quadratic formula:
x = (-(20) ± √((20)^2 - 4(4)(29))) / (2(4))
Simplifying further:
x = (-20 ± √(400 - 464)) / 8
x = (-20 ± √(-64)) / 8
x = (-20 ± 8i) / 8
Now, we can simplify the expression:
x = -20/8 ± (8i)/8
x = -5/2 ± i
Therefore, the roots of the given quadratic equation are:
x = -5/2 + i
x = -5/2 - i
6t^3 - 8t^8
B.
12t^6 - 4t^5
C.
6t^2 - 8t^4
D.
6t^3 - 4t^5
Answer:
Step-by-step explanation:
the vertex of the function is (-2, -1)
Answer:3400
Step-by-step explanation:
To find the amount of money in the account after 14 years with continuous compound interest, we can use the formula A = P * e^(rt), where P is the principal amount, e is Euler's number, r is the interest rate per year, and t is the number of years. Substituting the values into the formula, we find that the final amount in the account is approximately $3831.
To find the amount of money in the account after 14 years, we can use the formula for continuous compound interest, which is given by the formula:
A = P * e^(rt)
A is the final amount in the account (what we're trying to find)
P is the principal amount (the initial investment of $2,500)
e is Euler's number (approximately 2.71828)
r is the interest rate per year (2.1% or 0.021)
t is the number of years (14)
Substituting the values into the formula:
A = $2500 * e^(0.021 * 14)
Using a calculator, we can find that the final amount in the account is approximately $3831.
#SPJ2
Which describes the motion of the box based on the resulting free-body diagram?
It is moving up with a net force of 20 N.
It is moving to the right with a net force of 10 N.
It is in dynamic equilibrium with a net force of 0 N.
It is in static equilibrium with a net force of 0 N.
Mark this and return
Answer:
It is in static equilibrium with a net force of 0 N.
Step-by-step explanation:
EDGE21
I'm not sure if it is dynamic or static equilibrium but if I had to choose I'd say dynamic
A.
9 ft
B.
18 ft
C.
36 ft
D.
54 ft