The united states population in 1950 was 151 million. By 1990 it had increased by 65%. What was the 1990 population?

Answers

Answer 1
Answer:

Answer:

249.15 million

Step-by-step explanation:

151(1.65)=249.15

Answer 2
Answer:

To calculate the US population in 1990, we increase the 1950 population of 151 million by 65%, resulting in an estimated population of about 249.15 million.

To answer the question, we need to find out how much the United States population increased from 1950 to 1990. We know that the US population in 1950 was 151 million and that it increased by 65% by 1990.

First, we need to calculate the amount that represents the 65% increase from 151 million. We can do this by multiplying 151 million by 65/100. This will give us about 98.15 million.

Then, we add this increase to the initial population in 1950, which gives us the 1990 population. So, if we add 98.15 million to 151 million, we get a 1990 population estimate of approximately 249.15 million.

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Mary deposits R400 every three months into a bank account earning interest at 16% per year, compounded quarterly. The approximate time that it will take Mary to save R40000 is

Answers

Answer:

The approximate time that it will take Mary to save R40000 is 29 years

Step-by-step explanation:

A= p(1+r/n)^nt

t = log(A/P) / n[log(1 + r/n)]

A = R40000

n = 4

P = R400

r = 16%

t = log(A/P) / n[log(1 + r/n)]

= log(40,000 / 400) / 4{log(1+0.16/4)}

= log(100) / 4{log(1+0.04)}

= 2 / 4{log(1.04)}

= 2 / 4(0.0170)

= 2 / 0.068

= 29.41

t = 29.41 years

Approximately 29 years

The approximate time that it will take Mary to save R40000 is 29 years

What is the slope of the line?

Answers

Answer:

12

Step-by-step explanation:

72/6=12

48/4=12

Given ƒ(x) = 8x + 25, find x when ƒ(x) = 9.
A) -2
B) -1
C) 0
D) 2

Answers

A)-2
9=8x+25
-16=8x
X=-2

Sasha solved an equation, as shown below:Step 1: 8x = 56
Step 2: x = 56 – 8
Step 3: x = 48

Part B: How many solutions does this equation have? (4 points)

Answers

corrections
8x=56
divide both side by 8
x=7

A sound wave is given the following equation:y= 8 sin(512πt) where t= time in seconds.



How many cycles will occur between t=2 and t=3.5 seconds?

Answers

The number of cycles that will occur between t = 2 and t = 3.5 seconds is 384.

How to estimate the standard equation of a sine wave?

Given, y = 8 sin(512πt)

where t = time in seconds.

The standard equation of a sine wave is:

y = A sin(2πfx + B) + C

where A exists the amplitude

f exists the frequency

B exists the phase shift

C is the vertical offset.

In this case:

2πf = 512π

f = 256

This means there are 256 cycles per second.  

The number of cycles between t = 2 and t = 3.5 exists:

(3.5 − 2) × 256

= 384

Therefore, the number of cycles that will occur between t = 2 and t = 3.5 seconds is 384.

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Answer:

384

Step-by-step explanation:

Standard equation of a sine wave is:

y = A sin(2πf x + B) + C

where A is the amplitude, f is the frequency, B is the phase shift, and C is the vertical offset.

In this case:

2πf = 512π

f = 256

This means there are 256 cycles per second.  The number of cycles between t = 2 and t = 3.5 is:

(3.5 − 2) × 256

384

Use parentheses to make 5+4×3×3

Answers

the aNSWER IS 41..AM I RIGHT?
are you asking for the parenthesis so that they can be in order or are you asking for the answer? either way, here you go:

=5+[(4x3)x3]
=5+12x3
=5+36
=41