The monthly electric bills in acity have a mean of $86 and a
standard deviation of $18. Find
the z-scores that correspond
to a utility bill of $160.

Answers

Answer 1

Answer:

Step-by-step explanation:

Related Questions

Angle P is 3 more than twice angle M. If the two angles are complementary, find the measure of the two angles.
Marina is currently 14 years older than her cousin joey. in 5 years she will be 3 times as old as joey. if you let x represent joey's current age, what expression can you use to represent marina's current age?
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Wwhat the next number should be. 1 3 4 7 11 18 29 ___
What is the answer to y=-5x+13

Find the unknown length. Round to the nearest tenth if necessary.

Answers

Answer:

a = 7.4

Step-by-step explanation:

Since this is a right triangle, we will use the Pythagorean theorem:

c^2 = a^2 + b^2

28^2 = a^2 + 27^2

784 = a^2 + 729

55 = a^2

a = 7.4

Answer:

55 i believe

28 + 27 = 55

You have 6 pints of glaze. It takes 7/8 of a pint to glaze a bowl and 9/16 of a pint to glaze a plate.a. how many bowls could you glaze
b. how many plates can you glaze
c. how much glaze will be left over?

Answers

Part a) how many bowls could you glaze

we know that

You have $6$ pints of glaze. It takes $7/8$ of a pint to glaze a bowl

To find the number of bowls divide $6$ by $7/8$

$(6)/((7/8))} =(48)/(7) =6.86\ bowls$

therefore

the answer part a) is equal to

$6\ bowls$

Part b) how many plates can you glaze

You have $6$ pints of glaze. It takes $9/16$ of a pint to glaze a plate

To find the number of plates divide $6$ by $9/16$

$(6)/((9/16))} =(96)/(9) =10.67\ plates$

therefore

the answer part b) is equal to

$10\ plates$

Part c) how much glaze will be left over?

In the Part a)

$6-6 *(7)/(8) =6-(42)/(8) =(48)/(8) -(42)/(8)= (3)/(4)\ pint\ of \ glaze\ left$

In the Part b)

$6-10 *(9)/(16) =6-(45)/(8) =(48)/(8) -(45)/(8)= (3)/(8)\ pint\ of \ glaze\ left$

A. 6 = 48/8, now / (7/8) 6 bowlsB. 6 = 96/16, now / (9/16) 10 platesC. After 6 bowls you would have 6/8 glaze left, After 10 plates you would have 6/16 glaze left

What is 194 in radical form

Answers

The radical form of 194 = √2 x √97

To find the radical form of 194,

we need to factorize it into its prime factors.

So, let's start by dividing 194 by the smallest prime factor, which is 2,

⇒ 194 ÷ 2 = 97

We can see that 97 is a prime number,

so we can't divide it any further.

Therefore, the prime factorization of 194 is,

⇒ 194 = 2 x 97

Now, we can write the radical form of 194,

⇒√194 = √(2 x 97)

We can simplify this expression by breaking it down into the product of two separate square roots:

⇒ √(2 x 97) = √2 x √97

⇒The radical form of 194 is √2 x √97.

To learn more about radical form visit:

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194 in radical form is just √194. I don't believe any square roots go into it. Hope that helps. :)

Given a polynomial function f(x), describe the effects on the y-intercept, regions where the graph is increasing and decreasing, and the end behavior when the following changes are made. Make sure to account for even and odd functions.When f(x) becomes f(x) − 3
When f(x) becomes −2 ⋅ f(x)

Answers

First of all, let's review the definition of some concepts.

Even and odd functions:

A function is said to be even if its graph is symmetric with respect to the $y-axis$ , that is:

$y=f(x) \ is \ \mathbf{even} \ if, \ for \ each \ x \ in \ the \ domain \ of \ f, \n f(-x)=f(x)$

On the other hand, a function is said to be odd if its graph is symmetric with respect to the origin, that is:

$y=f(x) \ is \ \mathbf{odd} \ if, \ for \ each \ x \ in \ the \ domain \ of \ f, \n f(-x)=-f(x)$

Analyzing each question for each type of functions using examples of polynomial functions. Thus:

FOR EVEN FUNCTIONS:

1. When $f(x)$ becomes $f(x)-3$

1.1 Effects on the y-intercept

We need to find out the effects on the y-intercept when shifting the function $f(x)$ into:

$f(x)-3$

We know that the graph $f(x)$ intersects the y-axis when $x=0$ , therefore:

$y=f(0) \ is \ the \ y-intercept \ of \ f$

So:

$y=f(0)-3 \ is \ the \ new \ y-intercept$

So the y-intercept of $f(x)-3$ is three units less than the y-intercept of $f(x)$

1.2. Effects on the regions where the graph is increasing and decreasing

Given that you are shifting the graph downward on the y-axis, there is no any effect on the intervals of the domain. The function $f(x)-3$ increases and decreases in the same intervals of $f(x)$

1.3 The end behavior when the following changes are made.

The function is shifted three units downward, so each point of $f(x)-3$ has the same x-coordinate but the output is three units less than the output of $f(x)$ . Thus, each point will be sketched as:

$For \ y=f(x): \n P(x_(0),f(x_(0))) \n \n For \ y=f(x)-3: \n P(x_(0),f(x_(0))-3)$

FOR ODD FUNCTIONS:

2. When $f(x)$ becomes $f(x)-3$

2.1 Effects on the y-intercept

In this case happens the same as in the previous case. The new y-intercept is three units less. So the graph is shifted three units downward again.

An example is shown in Figure 1. The graph in blue is the function:

$y=f(x)=x^3-x$

and the function in red is:

$y=f(x)-3=x^3-x-3$

This function is odd, so you can see that:

$y-intercept \ of \ f(x)=0 \n y-intercept \ of \ f(x)-3=-3$

2.2. Effects on the regions where the graph is increasing and decreasing

The effects are the same just as in the previous case. So the new function increases and decreases in the same intervals of $f(x)$

In Figure 1 you can see that both functions increase and decrease at the same intervals.

2.3 The end behavior when the following changes are made.

It happens the same, the output is three units less than the output of $f(x)$ . So, you can write the points just as they were written before.

So you can realize this concept by taking a point with the same x-coordinate of both graphs in Figure 1.

FOR EVEN FUNCTIONS:

3. When $f(x)$ becomes $-2.f(x)$

3.1 Effects on the y-intercept

As we know the graph $f(x)$ intersects the y-axis when $x=0$ , therefore:

$y=f(0) \ is \ the \ y-intercept \ again$

And:

$y=-2f(0) \ is \ the \ new \ y-intercept$

So the new y-intercept is the negative of the previous intercept multiplied by 2.

3.2. Effects on the regions where the graph is increasing and decreasing

In the intervals when the function $f(x)$ increases, the function $-2f(x)$ decreases. On the other hand, in the intervals when the function $f(x)$ decreases, the function $-2f(x)$ increases.

3.3 The end behavior when the following changes are made.

Each point of the function $-2f(x)$ has the same x-coordinate just as the function $f(x)$ and the y-coordinate is the negative of the previous coordinate multiplied by 2, that is:

$For \ y=f(x): \n P(x_(0),f(x_(0))) \n \n For \ y=-2f(x): \n P(x_(0),-2f(x_(0)))$

FOR ODD FUNCTIONS:

4. When $f(x)$ becomes $-2f(x)$

See example in Figure 2

$y=f(x)=x^3-x$

and the function in red is:

$y=-2f(x)=-2(x^3-x)$

4.1 Effects on the y-intercept

In this case happens the same as in the previous case. The new y-intercept is the negative of the previous intercept multiplied by 2.

4.2. Effects on the regions where the graph is increasing and decreasing

In this case it happens the same. So in the intervals when the function $f(x)$ increases, the function $-2f(x)$ decreases. On the other hand, in the intervals when the function $f(x)$ decreases, the function $-2f(x)$ increases.

4.3 The end behavior when the following changes are made.

Similarly, each point of the function $-2f(x)$ has the same x-coordinate just as the function $f(x)$ and the y-coordinate is the negative of the previous coordinate multiplied by 2.

The y-intercept of  is  .
Of course, it is 3 less than  , the y-intercept of  .
Subtracting 3 does not change either the regions where the graph is increasing and decreasing, or the end behavior. It just translates the graph 3 units down.
It does not matter is the function is odd or even.

is the mirror image of  stretched along the y-direction.
The y-intercept, the value of  for  , iswhich is  times the y-intercept of  .Because of the negative factor/mirror-like graph, the intervals where  increases are the intervals where  decreases, and vice versa.
The end behavior is similarly reversed.
If  then  .
If  then  .
If  then  .
The same goes for the other end, as  tends to  .
All of the above applies equally to any function, polynomial or not, odd, even, or neither odd not even.
Of course, if polynomial functions are understood to have a non-zero degree,  never happens for a polynomial function.

What is the coefficient of x in the division (18x^3+12x^2-3x)/6x^2?A.
3

B.
2

C.
-0.5

D.
-3

Answers

Answer:

Step-by-step explanation:

Given : $(18x^3+12x^2-3x)/(6x^2)$

To Find: What is the coefficient of x in the division

Solution:

$(18x^3+12x^2-3x)/(6x^2)$

On Dividing we

Quotient = 3x+2

Remainder = -3x

So, coefficient of x in quotient = 3

Thus the coefficient of x in the division $(18x^3+12x^2-3x)/(6x^2)$ is 3

Hence Option A is correct

That would be A.... when you divide the trinomial in bracket by the $6x^(2)$ you will realize that the coefficient of the x is 3. If you want me to send a picture of the division please indicate.

Geometry HW! PLS HELP!

If UVW =~(congruent symbol) EFC, what is the measure of

Answers

The measure of angle FEC from the given triangle FCE is 51°. Therefore, option D is the correct answer.

Given that, ΔUVW≅ΔEFC.

What is the congruence theorem?

Triangle congruence theorem or triangle congruence criteria help in proving if a triangle is congruent or not. The word congruent means exactly equal in shape and size no matter if we turn it, flip it or rotate it.

From the given triangle UVW, the measure of ∠U=51° and ∠W=82°.

We know that, the corresponding parts of congruent triangle are equal.

Here, ∠FCE=∠W=82°

∠FEC=∠U=51°

The measure of angle FEC from the given triangle FCE is 51°. Therefore, option D is the correct answer.

To learn more about the congruent theorem visit:

brainly.com/question/24033497.

#SPJ2

Answer:

D. 51

Step-by-step explanation:

If UVW is congruent to EFC then FEC must be congruent to VUW