Joan bought a soft drink for 6.50 dollars and 12 candy bars. She spent a total of 65 dollars. How much did each candy bar cost? Which equation matches this problem?

Answers

Answer 1
Answer:

Answer:

0.406 (3 d.p)

Step-by-step explanation:

Let's call the cost of each candy bar "x" dollars. We can set up an equation to represent the situation:

6.50 + 12x = 65

This equation represents the problem. Now, we can solve for "x" to find the cost of each candy bar.

6.50 + 12x = 65

12x = 65 - 6.50

12x = 58.50

x = 58.50/12

x = 0.406 (3 d.p)

d.p means decimal point

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a) -7.5
b) -3
c) 2.5
d) 3

Answers

What is the slope of the line 6x-2y=15?
 Rewrite the equation in the y = mx + b form
-2y = -6x+15
y = 3x + 15

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So,
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the slope is m=3 in this case

What’s the value of y ?

Answers

X = 3. So 3x3 is 9, and then subtract 2 is 7. Y=7 Answer is B.

Which transformations are needed to change the parent cosine function to y= 3cos(10(x-pi) )?

Answers

The parent cosine function can be transformed and translated. So, from the basic function cos(x) we can obtain function acos(bx+c). In our case, a=3- amplitude, b=10- the period change and c=-pi- the phase shift. So, the parent cosine function is mutiplied with 3 (which gives the amplitude of the function, 3*0.5=1.5). The period of the function is changed, and is 2pi/b=2pi/10=pi/5 and the cos(x) is phase shifted for c/b=-pi/10.

Answer:

I think it´s B

Step-by-step explanation:

Find the area of the circle given the diameter is 8. Use 3.14 for pi

Answers

Answer:

A = 50.265482457437 or A = 50.27 or A = 50.265

Step-by-step explanation:

What vaule of b makes y=2x+b the same as y=2x?

Answers

Answer:

Step-by-step explanation:

hello :

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y=2x means : y=2x+0    so : b=0

Please solve equations by completing square

Answers

x^2-4x+1=0\n x^2-4x+4-3=0\n (x-2)^2=3\n |x-2|=\sqrt3\n x-2=\sqrt3 \vee x-2=-\sqrt3\n x=2+\sqrt3 \vee x=2-\sqrt3

x^2+6x-9=0\n x^2+6x+9-18=0\n (x+3)^2=18\n |x+3|=√(18)=3\sqrt2\n x+3=3\sqrt2 \vee x+3=-3\sqrt2\n x=-3+3\sqrt2 \vee x=-3-3\sqrt2\n

x^2+20x+3=0\n x^2+20x+100-97=0\n (x+10)^2=97\n |x+10|=√(97)\n x+10=√(97) \vee x+10=-√(97)\n x=-10+√(97) \vee x=-10-√(97)

x^2-2x-5=0\n x^2-2x+1-6=0\n (x-1)^2=6\n |x-1|=\sqrt6\n x-1=\sqrt6 \vee x-1=-\sqrt6\n x=1+\sqrt6 \vee x=1-\sqrt6